怎么判断两个时间的时间差ios开发

Posted 2023-03-20

参考技术A 计算两个时间差的两个函数
两个时间之差
- (NSString *)intervalFromLastDate: (NSString *) dateString1 toTheDate:(NSString *) dateString2

NSArray *timeArray1=[dateString1 componentsSeparatedByString:@"."];
dateString1=[timeArray1 objectAtIndex:0];

NSArray *timeArray2=[dateString2 componentsSeparatedByString:@"."];
dateString2=[timeArray2 objectAtIndex:0];

NSLog(@"%@.....%@",dateString1,dateString2);
NSDateFormatter *date=[[NSDateFormatter alloc] init];
[date setDateFormat:@"yyyy-MM-dd HH:mm:ss"];

NSDate *d1=[date dateFromString:dateString1];

NSTimeInterval late1=[d1 timeIntervalSince1970]*1;

NSDate *d2=[date dateFromString:dateString2];

NSTimeInterval late2=[d2 timeIntervalSince1970]*1;

NSTimeInterval cha=late2-late1;
NSString *timeString=@"";
NSString *house=@"";
NSString *min=@"";
NSString *sen=@"";

sen = [NSString stringWithFormat:@"%d", (int)cha%60];
// min = [min substringToIndex:min.length-7];
// 秒
sen=[NSString stringWithFormat:@"%@", sen];

min = [NSString stringWithFormat:@"%d", (int)cha/60%60];
// min = [min substringToIndex:min.length-7];
// 分
min=[NSString stringWithFormat:@"%@", min];

// 小时
house = [NSString stringWithFormat:@"%d", (int)cha/3600];
// house = [house substringToIndex:house.length-7];
house=[NSString stringWithFormat:@"%@", house];

timeString=[NSString stringWithFormat:@"%@:%@:%@",house,min,sen];
[date release];

return timeString;


一个时间距现在的时间

- (NSString *)intervalSinceNow: (NSString *) theDate

NSArray *timeArray=[theDate componentsSeparatedByString:@"."];
theDate=[timeArray objectAtIndex:0];

NSDateFormatter *date=[[NSDateFormatter alloc] init];
[date setDateFormat:@"yyyy-MM-dd HH:mm:ss"];
NSDate *d=[date dateFromString:theDate];

NSTimeInterval late=[d timeIntervalSince1970]*1;

NSDate* dat = [NSDate date];
NSTimeInterval now=[dat timeIntervalSince1970]*1;
NSString *timeString=@"";

NSTimeInterval cha=late-now;

if (cha/3600<1)
timeString = [NSString stringWithFormat:@"%f", cha/60];
timeString = [timeString substringToIndex:timeString.length-7];
timeString=[NSString stringWithFormat:@"剩余%@分", timeString];


if (cha/3600>1&&cha/86400<1)
timeString = [NSString stringWithFormat:@"%f", cha/3600];
timeString = [timeString substringToIndex:timeString.length-7];
timeString=[NSString stringWithFormat:@"剩余%@小时", timeString];

if (cha/86400>1)

timeString = [NSString stringWithFormat:@"%f", cha/86400];
timeString = [timeString substringToIndex:timeString.length-7];
timeString=[NSString stringWithFormat:@"剩余%@天", timeString];


[date release];
return timeString;
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