python/MySQL练习题

Posted 2020-09-22

python/MySQL练习题(二)

21、查询各科成绩前三名的记录:(不考虑成绩并列情况)

 1  select score.sid,score.course_id,score.num,T.first_num,T.second_num from score left join
 2     (
 3     select
 4         sid,
 5         (select num from score as s2 where s2.course_id = s1.course_id order by num desc limit 0,1) as first_num,
 6         (select num from score as s2 where s2.course_id = s1.course_id order by num desc limit 3,1) as second_num
 7     from
 8         score as s1
 9     ) as T
10     on score.sid =T.sid
11     where score.num <= T.first_num and score.num >= T.second_num

22、查询每门课程被选修的学生数

1 SELECT count(student_id) from score LEFT JOIN course on course.cid=score.course_id
2 GROUP BY course_id
3 HAVING COUNT(1) >4

23、查询出只选修了一门课程的全部学生的学号和姓名

1 SELECT student.sid,student.sname from score LEFT JOIN student on student.sid=score.student_id
2 LEFT JOIN course on course.cid=score.course_id
3 GROUP BY student_id
4 HAVING count(score.course_id)=‘1‘

24、查询男生、女生的人数

1 SELECT gender,count(sid) from student
2 GROUP BY gender
3 HAVING count(sid)

25、查询姓“张”的学生名单

1 SELECT * from student where sname like ‘张%‘

26、查询同名同姓学生名单，并统计同名人数

1 SELECT sname,COUNT(sname) from student
2 GROUP BY sname
3 HAVING COUNT(sname)

27、查询每门课程的平均成绩，结果按平均成绩升序排列，平均成绩相同时，按课程号降序排列

1  SELECT course_id,avg(num) from score LEFT JOIN course on course.cid=score.course_id
2  GROUP BY course_id
3  ORDER BY avg(num) asc 

28、查询平均成绩大于85的所有学生的学号、姓名和平均成绩

1  SELECT student.sid,student.sname,avg(num) from score LEFT JOIN student on student.sid=score.student_id
2  GROUP BY student_id
3  HAVING avg(num) > 85

29、查询课程名称为“物理”，且分数低于60的学生姓名和分数

1 SELECT student.sname,score.num  from score LEFT JOIN student on student.sid=score.student_id
2 LEFT JOIN course on course.cid=score.course_id
3 where course.cname=‘生物‘ and score.num <60

30、查询课程编号为003且课程成绩在80分以上的学生的学号和姓名

1 SELECT student.sid,student.sname from score LEFT JOIN course on course.cid=score.course_id
2 LEFT JOIN student on student.sid=score.student_id
3 where course.cid=‘3‘ and num > 80

31、求选了课程的学生人数

1 SELECT COUNT(c) from
2 (SELECT count(student_id)as c from score GROUP BY student_id)as A

32、查询选修“李平”老师所授课程的学生中，成绩最高的学生姓名及其成绩

1 SELECT sname,num from score
2 LEFT JOIN course on course.cid=score.course_id
3 LEFT JOIN student on student.sid=score.student_id
4 LEFT JOIN teacher on teacher.tid=course.teacher_id
5 where teacher.tname=‘李平老师‘
6 GROUP BY student_id
7 ORDER BY num DESC
8 LIMIT 1

33、查询各个课程及相应的选修人数

1 SELECT cname,COUNT(1)from score LEFT JOIN course on course.cid=score.course_id
2 GROUP BY course_id

34、查询不同课程但成绩相同的学生的学号、课程号、学生成绩

1 select A1.student_id,A1.course_id,A2.course_id,A1.num,A2.num from score as A1 ,score as A2
2 where A1.course_id!=A2.course_id and A1.num=A2.num
3 GROUP BY student_id

35、查询每门课程成绩最好的前两名

 1    select score.sid,score.course_id,score.num,T.first_num,T.second_num from score left join
 2     (
 3     select
 4         sid,
 5         (select num from score as s2 where s2.course_id = s1.course_id order by num desc limit 0,1) as first_num,
 6         (select num from score as s2 where s2.course_id = s1.course_id order by num desc limit 1,1) as second_num
 7     from
 8         score as s1
 9     ) as T
10     on score.sid =T.sid
11     where score.num <= T.first_num and score.num >= T.second_num

36、检索至少选修两门课程的学生学号

1 -- SELECT count(A.c) from (select count(1)as c from score GROUP BY course_id)as A
2 SELECT student_id from score LEFT JOIN student on student.sid=score.student_id
3 GROUP BY student_id
4 HAVING count(1) > 2

37、查询全部学生都选修的课程的课程号和课程名

1 select course_id from score GROUP BY course_id HAVING COUNT(1)=(select count(1) from student)

38、查询没学过“李平”老师讲授的任一门课程的学生姓名

 1 SELECT
 2     student.sname
 3 FROM
 4     student
 5 WHERE
 6     sid NOT IN (
 7         SELECT
 8             course_id
 9         FROM
10             score
11         LEFT JOIN course ON course.cid = score.course_id
12         LEFT JOIN student ON student.sid = score.student_id
13         LEFT JOIN teacher ON teacher.tid = course.teacher_id
14         WHERE
15             teacher.tname = ‘李平老师‘
16     )

39、查询两门以上不及格课程的同学的学号及其平均成绩

1 SELECT student_id,avg(num) from score where num <60 GROUP BY student_id HAVING count(1)>2

40、检索“004”课程分数小于60，按分数降序排列的同学学号

1 SELECT student_id from score where course_id=4 and num <60 ORDER BY num DESC

41、删除“002”同学的“001”课程的成绩

1 DELETE from score where student_id=2 and course_id=1