Python练习题-1
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最近这几天的学习总练习:
#! /usr/bin/env python # -*- coding: utf-8 -*- # Date: 2017/6/9 #练习一/1:实现用户输入用户名和密码,当用户名为seven且密码为123时,显示登录成功,否则失败. # d = {‘seven‘:‘123‘} # while True: # user = input(‘Enter your username:‘) # passwd = input(‘Enter your password:‘) # if not user and not passwd: # continue # elif user in d and passwd == d[user]: # print(‘login ok‘) # break # else: # print(‘login fail‘) # 练习一/2:实现用户输入用户名和密码,当用户名为seven且密码为123时,显示登录成功,否则失败.允许失败是重复输入三次 # d = {‘seven‘:‘123‘} # n = 0 # while n < 3: # user = input(‘Enter your username:‘) # passwd = input(‘Enter your password:‘) # if not user and not passwd: # continue # elif user in d and passwd == d[user]: # print(‘login ok‘) # break # else: # print(‘login fail‘) # n += 1 # 练习一/3:实现用户输入用户名和密码,当用户名为seven或alex且密码为123时,显示登录成功,否则失败.允许失败是重复输入三次 # d = {‘seven‘:‘123‘,‘alex‘:‘123‘} # n = 3 # while n > 0 : # user = input(‘Enter your username:‘) # passwd = input(‘Enter your password:‘) # if not user and not passwd: # continue # elif user in d and passwd == d[user]: # print(‘login ok‘) # break # else: # n -= 1 # print(‘You can also try to log in‘,n,‘times‘) #练习二/1:使用while循环实现输出2-3+4-5+6...+100的和 # n = 2 # jsum = 0 # osum = 0 # while n < 101: # if n % 2 == 1: # jsum += n # n += 1 # else: # osum += n # n += 1 # print(osum-jsum) #练习二/2:使用for循环实现输出1-2+3-4+5-6..+99的和 # jsum = 0 # osum = 0 # for x in range(1,100): # if x % 2 == 1: # jsum += x # else: # osum += x # print(osum-jsum) #练习二/3:使用while循环实现输出1,2,3,4,5,7,8,9,11,12 # n = 1 # while n < 13: # if n == 6 or n ==10: # n += 1 # continue # else: # print(n,end = ‘ ‘) # n += 1 #练习二/3:使用while循环实现输出1-100内的所有奇数 # n = 1 # while n < 101: # if n % 2 == 1: # print(n) # n += 1 # else: # n += 1 #练习二/3:使用while循环实现输出1-100内的所有偶数 # n = 1 # while n < 101: # if n % 2 == 1: # n += 1 # else: # print(n) # n += 1 # 练习三: # name = " alex " # a.移除name变量对应的值的两边的空格,并输入移除有的内容 # print(name.strip()) # b.判断name变量对应的值是否以"al"开头,并输出结果 # print(name.startswith(‘a1‘)) # c.判断name变量对应的值是否以"x"结尾,并输出结果 # print(name.endswith(‘x‘)) # d.将name变量对应的值中的"l"替换为"p",并输出结果 # print(name.replace(‘l‘,‘p‘)) # e.将name变量对应的值根据"l"分割,并输出结果 # print(name.split(‘l‘)) # f.请问,上一题e分割之后得到的值是什么类型 # print(type(name.split(‘e‘))) # g.将name变量对应的值中变大写,并输出结果 # print(name.upper()) # h.将name变量对应的值中变大小写,并输出结果 # print(name.title()) # i.请输出name变量对应的值的第2个字符? # print(name[1]) # j.请输出name变量对应的值的前3个字符? # print(name[0:3]) # k.请输出name变量对应的值的后2个字符? # print(name[0:-2]) # l.请输出name变量对应的值中"e"所在的索引位置? # print(name.index(‘e‘)) # 练习四: # 写代码,有如下列表,按照要求实现每一个功能 # li = [‘alex‘,‘eric‘,‘rain‘,‘abc‘,‘123‘,‘aaa‘] # a.计算列表长度并输出 # print(len(li)) # b.列表中追加元素"seven",并输出添加后的列表 # li.append(‘seven‘) # print(li) # c.请在列表的第1个位置插入元素"Tony",并输出添加后的列表 # li.insert(1,‘Tony‘) # print(li) # d.请修改列表第2个位置的元素为"Kelly",并输出修改后的列表 # li[2]=‘Kelly‘ # print(li) # e.请删除列表中的元素"eric",并输出修改后的列表 # li.remove(‘eric‘) # print(li) # f.请删除列表中的第2个元素,并输出删除元素的值和删除元素后的列表 # print(li.pop(1)) # print(li) # g.请删除列表中的第3个元素,并输出删除元素后的列表 # li.pop(2) # print(li) # h.请删除列表中的第2至4个元素,并输出删除元素后的列表 # del li[2:5] # print(li) # i.请将列表所有的元素反转,并输出反转后的列表 # li.reverse() # print(li) # 练习五: #正左直角 # for i in range(10): # for j in range(0,i): # print(‘*‘,end = ‘ ‘) # print(‘‘) #倒左直角 # for i in range(10): # for j in range(0,10-i): # print(‘*‘,end = ‘ ‘) # print(‘‘) #倒三角 # for i in range(10): # for j in range(0,i): # print(end = ‘ ‘) # for k in range(0,10 - i): # print(‘*‘,end = ‘ ‘) # print(‘‘) #正三角 # for i in range(10): # for j in range(0,10 - i): # print(end = ‘ ‘) # for k in range(0,i): # print(‘*‘,end = ‘ ‘) # print(‘‘) #九九乘法表 # for i in range(1,10): # for j in range(1,i+1): # print(‘%s*%s=%s‘%(i,j,i*j),end = ‘ ‘) # print(‘‘) # 练习六 #取出列表中的名字，年龄，出生的年，月，日 # data=[‘alex‘,49,[1900,3,18]] # name,age,birthday = data=[‘alex‘,49,[1900,3,18]] # print(name) # print(age) # print(birthday) #去掉重复 # names=[‘egon‘,‘alex‘,‘egon‘,‘wupeiqi‘] # name = set(names) # print(name) #去掉重复，且保证列表顺序与原来保持一致 # names=[‘egon‘,‘alex‘,‘egon‘,‘wupeiqi‘] # tmp = [] # for n in names: # if n not in tmp: # tmp.append(n) # print(tmp) #去掉重复，且保证列表顺序与原来保持一致 # names=[[1,2],3,[1,2],4] # tmp = [] # for n in names: # if n not in tmp: # tmp.append(n) # print(tmp) #统计s=‘hello alex alex say hello sb sb‘中每个单词的个数 # s=‘hello alex alex say hello sb sb‘ # l = s.split() # st = set(l) # for x in st: # print(x,‘的个数为‘,l.count(x)) # for x in s: # print(len(x)) #练习七 #not and or 的优先级是 not>and>or 既优先判断 not 没有not判断 and 没有and 最后判断 or,如果有括号先判断括号内的 # if True or False and False: # print(‘yes‘) # else: # print(‘no‘) #输出结果为?为什么? True or False ===> True 结果为:yes # if (True or False) and False: # print(‘yes‘) # else: # print(‘no‘) #输出结果为?为什么? True and False ===> False 结果为:no #练习八 #编写if多分支,猜老男孩的年纪 # age = int(input(‘Please enter your age:‘)) # tag = True # while tag: # user_input = input(‘Please enter your answer:‘) # if user_input.isdigit(): # user_input = int(user_input) # else: # continue # if int(user_input) > age: # print(‘Guess big!‘) # elif int(user_input) < age: # print(‘Guess small!‘) # elif int(user_input) == age: # print(‘Congratulations,you guessed it!‘) # tag = False #练习九 #用户输入用户名密码验证,验证通过后进入子循环,输入命令,命令若为q,则退出所有循环 # d = {‘abc‘:‘123‘} # tag = True # while tag: # user = input(‘Please enter your username:‘) # passwd = input(‘Please enter your password:‘) # if user in d and passwd == d[user]: # while tag: # cmd = input(‘>>:‘) # if cmd == ‘q‘: # tag = False # print(‘exit‘) # else: # print(cmd) #练习十 #循环取出元组中所有元素:方式一:while和for(按照索引),方式二:不按照索引的方式 # t=(1,2,3,4,5,6,7,8,9) # n = 0 # while n < len(t): # print(t[n]) # n += 1 # # for x in range(len(t)): # print(t[x]) # # for x in t: # print(x) #练习十一 #循环读取列表以及子列表中所有元素 # l=[1,2,[3,4],[5,6]] # for l in l: # if type(l) == list: # for s in l: # print(s) # else: # print(l) #练习十二#数据类型练习题: # 有十进制数n=10 # 转成二进制 # print(bin(10)) # 转成八进制 # print(oct(10)) # 转成十六进制 # print(hex(10)) #练习十三 #与用户交互,要求用户输入年龄和薪资,将用户输入的年龄转成整形,将用户输入的薪资转成浮点型 # age = int(input(‘Plese enter your age:‘)) # salary = float(input(‘Please enter your salary:‘)) # print(‘age:‘,age,‘salary:‘,salary) #练习十四 # 用户输入用户名,年纪,工作,爱好,格式化输出如下内容(使用%s和format两种方式) # ------------ info of Alex Li ----------- # Name : Alex Li # Age : 22 # job : Teacher # Hobbie: girl # ------------------ end ----------------- # name = input(‘Please enter your name:‘) # age = input(‘Please enter your age:‘) # job = input(‘Please enter your job:‘) # hobby = input(‘Please enter your hobbies:‘) # print(‘------------ info of %s -----------‘%name) # print(‘‘‘Name:%s # Age:%s # Job:%s # Hobby:%s # ‘‘‘%(name,age,job,hobby),end = ‘‘) # print(‘------------------ end -----------------‘) # print(‘------------ info of %s -----------‘%name) # info = ‘‘‘Name:{a} # Age:{b} # Job:{c} # Hobby:{d} # ‘‘‘ # print(info.format(a = name,b = age,c = job,d = hobby),end = ‘‘) # print(‘------------------ end -----------------‘) #练习十五 # s=‘alex say hello‘ # 切片取出第say # s = s.split() # print(s[1]) # 切片取出倒数后两个字符 # s = s.split() # print(s[1:3]) #练习十六 # 编写循环,让用户输入年纪,如果输入为空,或者不为数字,则重新输入 # tag = True # while tag: # age = input(‘Please enter your age:‘) # if age.isdigit(): # print(‘age:‘,age) # tag = False # 练习十七 # 用列表模拟上电梯的流程(队列) # 循环生成一个1000个值的列表(入队) # 循环取走这个1000个值(出队) # l = [] # n = 0 # for x in range(1000): # l.append(x) # while n < 1000: # print(l.pop(0)) # n += 1 # 用列表模拟把衣服放箱子里,然后取衣服的流程(堆栈) # 循环生成一个1000个值的列表(入栈) # 循环取走这个1000个值(出栈) # l = [] # n = 0 # for x in range(1000): # l.append(x) # while n < 1000: # print(l.pop()) # n += 1 #练习十八 # dicta={‘a‘:1,‘b‘:2,‘c‘:3,‘d‘:‘hello‘} # dictb={‘b‘:3,‘c‘:2,‘d‘:‘world‘,‘f‘:10} #两字典相加,不同的key对应的值保留,相同的key对应的值相加后保留,如果是字符串就拼接(字符串拼接‘hello‘+‘world‘得‘helloworld‘) # {‘a‘: 1, ‘b‘: 5, ‘c‘: 5, ‘d‘: ‘helloworld‘, ‘f‘: 10} # d = {} # d.update(dicta) # for k2,v2 in dictb.items(): # if k2 not in d: # d[k2] = v2 # elif k2 in d: # d[k2] = d[k2]+v2 # print(d) #练习十九 #此题egon老师未出完. #alex发表了朋友圈: # alex_msg=‘‘‘ # 我想淫一首小诗 # 歌颂我的同桌 # 她乌黑的头发 # 好像一直炸毛鸡 # ‘‘‘ # #eogn发表了朋友圈: # egon_msg=‘‘‘ # 总有文盲装文艺 # ‘‘‘ # comments={ # alex_msg:{ # ‘author‘:‘alex‘, # ‘comments‘:[ # (‘wupeiqi‘,‘真傻比‘), # (‘元昊‘,‘确实傻比‘), # (‘egon‘,‘同上‘) # ], # ‘thumb_counts‘:3, # }, # egon_msg:{ # ‘author‘:‘egon‘, # ‘comments‘:[ # (‘alex‘,‘说谁呢‘), # (‘元昊‘,‘你被开除了‘), # (‘wupeiqi‘,‘好刺激‘) # ], # ‘thumb_counts‘:2, # }, # } # #循环打印出朋友圈内容 # tag = True # while tag: # cmd = input(‘查看朋友圈?(y/n)‘) # if cmd == ‘y‘: # for k1,v1 in comments.items(): # print(k1) # for k2,v2 in v1.items(): # if type(v2) == list: # for u,s in v2: # print(‘%s:%s‘%(u,s)) # elif type(v2) != list: # print(‘%s:%s‘%(k2,v2)) # tag = False
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