c语言编程题：输入一个日期，计算出该日期是星期几？

Posted 2023-02-20 新时代键盘上的农民工

c语言编程题：输入一个日期，计算出该日期是星期几？

源代码如下：

/*
* author:X
* date:2021/9/17 18:49
* description:输入一个日期，计算出该日期是星期几？
*/

#include <stdio.h>
int leap(int year);
int main()

    int year, month, day, i;
    int m[12] =  31,28,31,30,31,30,31,31,30,31,30,31 ;
    printf("请输入要判断的年月日(格式如:2021 9 17 年月日之间用空格隔开)：");
    while (~scanf("%d %d %d", &year, &month, &day))
    
        if (day < 1 || month < 1 || month > 12 || year < 1 || year>10000|| day > m[month - 1])
        
            printf("%d/%d/%d 是不正确的日期\\n", year, month, day);
            return -1;
        
        if (leap(year))
            m[1] = 29;
        else
            m[1] = 28;
        int sum = 0;
        sum += day;
        for (i = 1; i < month; i++)
            sum += m[i - 1];
        for (i = 1; i < year; i++)
        
            sum += 365;
            if (leap(i))
                sum++;
        
        int  dx = sum % 7;
        if (dx == 0)
            printf("%d/%d/%d 是星期天\\n", year, month, day);
        else if (dx == 1)
            printf("%d/%d/%d 是星期一\\n", year, month, day);
        else if (dx == 2)
            printf("%d/%d/%d 是星期二\\n", year, month, day);
        else if (dx == 3)
            printf("%d/%d/%d 是星期三\\n", year, month, day);
        else if (dx == 4)
            printf("%d/%d/%d 是星期四\\n", year, month, day);
        else if (dx == 5)
            printf("%d/%d/%d 是星期五\\n", year, month, day);
        else if (dx == 6)
            printf("%d/%d/%d 是星期六\\n", year, month, day);
    
    return 0;


int leap(int year)                  //判断是否为闰年

    if (year % 400 == 0 || (year % 4 == 0 && year % 100 != 0))
        return 1;
    return 0;

测试结果：