3Sum
Posted IIcyZhao
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Given an array S of n integers, are there elements a, b, c in S such that a + b + c = 0? Find all unique triplets in the array which gives the sum of zero.
Note:
- Elements in a triplet (a,b,c) must be in non-descending order. (ie, a ? b ? c)
- The solution set must not contain duplicate triplets.
For example, given array S = -1 0 1 2 -1 -4, A solution set is: (-1, 0, 1) (-1, -1, 2)
class Solution
public:
vector<vector<int> > threeSum(vector<int> &num)
// Start typing your C/C++ solution below
// DO NOT write int main() function
vector<vector<int> > result;
set<vector<int> > record;
if (num.size() < 3)
return result;
sort(num.begin(), num.end());
vector<int> got;
int sum = 0;
for (int i = 0; i < num.size() - 2; ++i)
int low = i + 1;
int high = num.size() - 1;
while (low < high)
sum = num[i] + num[low] + num[high];
if (sum == 0)
got.push_back(num[i]);
got.push_back(num[low]);
got.push_back(num[high]);
if (record.find(got) == record.end())
record.insert(got);
result.push_back(got);
got.clear();
--high;
else if (sum > 0)
--high;
else
++low;
return result;
;
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