如何在EXCEL中筛选出工资最高和最低的两个人信息
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步骤如下：
1.打开excel文件后，选中数据列，点击开始选项中排序和筛选里的“筛选”；
2.选中的数据表格最上端就会出现筛选的符号；
3.找到工资列的筛选符号，鼠标左键，出现可选升序或降序的选项；
4.点击“降序”排列，即可找出最高工资的个人信息；
5.点击“升序”排列，即可找出最低工资的个人信息。
用高级筛选能实现吗？MIN涵数的作用是什么，谢谢
追答比如工资在C2:C50中，在C51和C52单元格分别输入：
=max(C2:C50) 最大值（最高工资）
=min(C2:C50) 最小值（最低工资）
整行信息的获取，下面公式可向右拖动复制：
=INDEX(A2:A50,MATCH(MAX($C$2:$C$50),$C$2:$C$50,0)) 最高工资行
=INDEX(A2:A50,MATCH(Min($C$2:$C$50),$C$2:$C$50,0)) 最低工资行
会，但感觉好象太简单了吧
如何让全局变量 int 高和低以在显示功能中打印？ （这两个变量显示最高和最低分）
【中文标题】如何让全局变量 int 高和低以在显示功能中打印？ （这两个变量显示最高和最低分）【英文标题】：How do I get Global variables int high and into low to print in display function? (These two variables display the highest and lowest marks) 【发布时间】：2020-10-02 21:49:56 【问题描述】：该计划的目的是为学生制作成绩单。在显示功能中显示最高和最低标记时出错。我在全局范围内声明了变量 int high 和 int low ，认为这可以解决问题-但是它仍然在显示中打印零。-有趣的事情是打印最高和最低 int min max 函数 ＃包括 使用命名空间标准；
int high; int low;
void studentDetails(string Name, string Surname, string School)
cout << "Please provide the following details below.";
cout << "\nName: ";
cin >> Name;
cout << "Surname: ";
cin >> Surname;
cout << "Name of School: ";
cin >> School;
getMarks (int& Eng, int& Maths, int& LO, int& His, int& CL, int& Art)
cout << "Please provide the mark obtained (0-100) for the following subjects.";
cout << "\nEnglish: ";
cin >> Eng;
while (Eng>=0 && Eng<=100)
cout << "Mathematics: ";
cin >> Maths;
while (Maths>=0 && Maths<=100)
cout << "Life Orientation: ";
cin >> LO;
while (LO>=0 && LO<=100)
cout << "History: ";
cin >> His;
while (His>=0 && His<=100)
cout << "Computer Literacy: ";
cin >> CL;
while (CL>=0 && CL<=100)
cout << "Art: ";
cin >> Art;
while (Art>=0 && Art<=100)
cout << "All marks have been recorded";
return 0;
void AverageYearMark(int avg, int& Eng, int& Maths, int& LO, int& His, int& CL, int& Art)
avg = (Eng + Maths + LO + His + CL + Art)/6;
cout << "\nThe average of the above marks is: ";
cout << avg;
minMax(int& Eng, int& Maths, int& LO, int& His, int& CL, int& Art)
int arr[] = Eng,Maths,LO,His,CL, Art;
int high = arr[0]; //highest mark
for(int i = 1; i<6; i++)
if(arr[i]>high)
high = arr[i];
cout << "Highest mark";
cout << high;
int low = arr[0]; // lowest mark
for(int i = 1; i<6; i++)
if(arr[i]<low)
low = arr[i];
cout << "Lowest mark";
cout << low;
return 0;
void passorFail (string dec, int& Eng, int& Maths, int& LO, int& His, int& CL, int& Art)
int arr[] = Maths,LO,His,CL, Art;
int counta = 0;
if(Eng>= 50)
counta++;
for(int i =0; i<5; i++)
if(arr[i]>50)
counta++;
if(counta>=4)
dec = "Pass";
else
dec = "Fail";
else
dec = "Fail";
cout << dec;
void awardDistinction(double& avg, int& Eng, int& Maths, int& LO, int& His, int& CL, int& Art)
int arr1[] = Eng,Maths,LO,His,CL, Art;
string arr2[6];
string overall;
string distinction = "distinction";
for(int i= 0; i<6;i++)
if(arr1[i]>=75)
arr2[i]= distinction;
else
arr2[i] = " ";
for (int i = 0; i<6; i++)
cout << arr2[i];
if(avg>=75)
overall = "distinction";
void codeSymbol(string (&symbol)[6], int (&code)[6],double& avg, int& Eng, int& Maths, int& LO, int& His, int& CL, int& Art)
int arr1[] = Eng,Maths,LO,His,CL, Art;
//symbol<string,6>;
//code<int,6>;
for (int i=0; i<6; i++)
if(arr1[i]>=80 && arr1[i]<=100)
symbol[i] = "A";
code[i] = 7;
if(arr1[i]>=70 && arr1[i]<=79)
symbol[i] = "B";
code[i] = 6;
if(arr1[i]>=60 && arr1[i]<=69)
symbol[i] = "C";
code[i] = 5;
if(arr1[i]>=50 && arr1[i]<=59)
symbol[i] = "D";
code[i] = 4;
if(arr1[i]>=40 && arr1[i]<=49)
symbol[i] = "E";
code[i] = 3;
if(arr1[i]>=30 && arr1[i]<=39)
symbol[i] = "F";
code[i] = 2;
if(arr1[i]>=0 && arr1[i]<=29)
symbol[i] = "FF";
code[i] = 1;
int avcode;
string avsym;
if(avg<=100 && avg>=80 )
avcode = 7;
avsym = "A";
if(avg<=79 && avg>=70 )
avcode = 6;
avsym = "B";
if(avg<=69 && avg>=60 )
avcode = 5;
avsym = "C";
if(avg<=59 && avg>=50 )
avcode = 4;
avsym = "D";
if(avg<=49 && avg>=40 )
avcode = 3;
avsym = "E";
if(avg<=39 && avg>=30 )
avcode = 2;
avsym = "F";
if(avg<=29 && avg>=0 )
avcode = 1;
avsym = "FF";
在下面的显示函数中打印最高和最低标记时出现错误-它是从 min max 函数打印的，但当我全局获取时却没有
void Dispay(string& Name, string& Surname, string& School, string (&symbol)[6] , int (&mark)[6], int (&code)[6], string (subject)[6])
cout <<"\n*******************************************************************************" << endl;
cout <<" STUDENT ACADEMIC RECORD " << endl;
cout <<" This program input the learner marks of matric level subjects and prints the student final report" << endl;
cout <<"*******************************************************************************" << endl;
cout <<"Name: " + Name + " " + Surname + " School: " + School;
cout <<"\n\nSubject \t\tMark\t\tSymbol\t\tCode" << endl;
for(int i = 0; i<6;i++)
cout << subject[i] << "\t" << mark[i]<< "%\t\t" + symbol[i] << "\t\t" << code[i] << "\n";
cout << "\nAverage Year Mark: " << " 32 " << " with symbol " << " D " << " and code " << " 4 " << endl;
cout << "\nOutcome: " << "Passed" << endl;
cout << "\nThe highest mark was: " << " -" <<high<< endl;
cout << "\nThe lowest mark was: " << " -" <<low<< endl;
cout <<"*******************************************************************************" << endl;
int main ()
string n; string sn; string s; string dec;
int Eng; int Maths; int LO; int His; int CL; int Art; int low; int high;
double avg = 0;
string subject[] = "English ","Mathematics ","Life Orientation ","History ","Computer Literacy","Art ";
string symbol[6];
int code[6];
studentDetails(n,sn,s);
getMarks(Eng, Maths, LO, His, CL, Art);
int mark[] = Eng, Maths, LO, His, CL, Art;
AverageYearMark(avg, Eng, Maths, LO, His, CL, Art);
minMax(Eng, Maths, LO, His, CL, Art);
passorFail(dec,Eng, Maths, LO, His, CL, Art);
awardDistinction(avg, Eng, Maths, LO, His, CL, Art);
codeSymbol(symbol,code,avg,Eng,Maths,LO,His,CL,Art);
Dispay(n,sn,s,symbol,mark,code,subject);
///Output:
Please provide the following details below.
Name: Imraan
Surname: JAcobs
Name of School: WIndereme
Please provide the mark obtained (0-100) for the following subjects.
English: 60
Mathematics: 85
Life Orientation: 62
History: 90
Computer Literacy: 96
Art: 97
All marks have been recorded
The average of the above marks is: 81Highest mark97Lowest mark60Pass distinction distinctiondistinctiondistinction
*******************************************************************************
STUDENT ACADEMIC RECORD
This program input the learner marks of matric level subjects and prints the student final report
*******************************************************************************
Name: School:
Subject Mark Symbol Code
English 60% C 5
Mathematics 85% A 7
Life Orientation 62% C 5
History 90% A 7
Computer Literacy 96% A 7
Art 97% A 7
Average Year Mark: 32 with symbol D and code 4
Outcome: Passed
The highest mark was: -0
The lowest mark was: -0
*******************************************************************************
Process returned 0 (0x0) execution time : 23.190 s
Press any key to continue.
【问题讨论】：
请慢慢阅读How to Ask。然后edit你的问题提供minimal reproducible example 仅供参考，std::string 类型应通过 reference 传递，或者如果您的函数未更改参数，则应通过 const 参考传递。这将避免编译器制作副本并将副本传递给您的函数。
建议：1) 使用空格而不是制表符。 2）格式（缩进你的代码）。
顺便说一句，您可以在同一遍数据中找到最高和最低标记。
【参考方案1】：
如果您已在文件开头定义为全局变量，请不要在您的 minmax 函数中再次定义 int low 和 int high。
在您的 main 函数中删除它们，因为您在那里第三次定义它们。你永远不会将后者作为参数传递给函数，所以幸运的是它们最终没有被使用。
这是代码的工作版本：
#include <iostream>
using namespace std;
int high, low;
void studentDetails(string Name, string Surname, string School)
cout << "Please provide the following details below.";
cout << "\nName: ";
cin >> Name;
cout << "Surname: ";
cin >> Surname;
cout << "Name of School: ";
cin >> School;
getMarks (int& Eng, int& Maths, int& LO, int& His, int& CL, int& Art)
cout << "Please provide the mark obtained (0-100) for the following subjects.";
cout << "\nEnglish: ";
cin >> Eng;
while (Eng>=0 && Eng<=100)
cout << "Mathematics: ";
cin >> Maths;
while (Maths>=0 && Maths<=100)
cout << "Life Orientation: ";
cin >> LO;
while (LO>=0 && LO<=100)
cout << "History: ";
cin >> His;
while (His>=0 && His<=100)
cout << "Computer Literacy: ";
cin >> CL;
while (CL>=0 && CL<=100)
cout << "Art: ";
cin >> Art;
while (Art>=0 && Art<=100)
cout << "All marks have been recorded";
return 0;
void AverageYearMark(int avg, int& Eng, int& Maths, int& LO, int& His, int& CL, int& Art)
avg = (Eng + Maths + LO + His + CL + Art)/6;
cout << "\nThe average of the above marks is: ";
cout << avg;
minMax(int& Eng, int& Maths, int& LO, int& His, int& CL, int& Art)
int arr[] = Eng,Maths,LO,His,CL, Art;
high = arr[0]; //highest mark
for(int i = 1; i<6; i++)
if(arr[i]>high)
high = arr[i];
cout << "Highest mark";
cout << high;
low = arr[0]; // lowest mark
for(int i = 1; i<6; i++)
if(arr[i]<low)
low = arr[i];
cout << "Lowest mark";
cout << low;
return 0;
void passorFail (string dec, int& Eng, int& Maths, int& LO, int& His, int& CL, int& Art)
int arr[] = Maths,LO,His,CL, Art;
int counta = 0;
if(Eng>= 50)
counta++;
for(int i =0; i<5; i++)
if(arr[i]>50)
counta++;
if(counta>=4)
dec = "Pass";
else
dec = "Fail";
else
dec = "Fail";
cout << dec;
void awardDistinction(double& avg, int& Eng, int& Maths, int& LO, int& His, int& CL, int& Art)
int arr1[] = Eng,Maths,LO,His,CL, Art;
string arr2[6];
string overall;
string distinction = "distinction";
for(int i= 0; i<6;i++)
if(arr1[i]>=75)
arr2[i]= distinction;
else
arr2[i] = " ";
for (int i = 0; i<6; i++)
cout << arr2[i];
if(avg>=75)
overall = "distinction";
void codeSymbol(string (&symbol)[6], int (&code)[6],double& avg, int& Eng, int& Maths, int& LO, int& His, int& CL, int& Art)
int arr1[] = Eng,Maths,LO,His,CL, Art;
for (int i=0; i<6; i++)
if(arr1[i]>=80 && arr1[i]<=100)
symbol[i] = "A";
code[i] = 7;
if(arr1[i]>=70 && arr1[i]<=79)
symbol[i] = "B";
code[i] = 6;
if(arr1[i]>=60 && arr1[i]<=69)
symbol[i] = "C";
code[i] = 5;
if(arr1[i]>=50 && arr1[i]<=59)
symbol[i] = "D";
code[i] = 4;
if(arr1[i]>=40 && arr1[i]<=49)
symbol[i] = "E";
code[i] = 3;
if(arr1[i]>=30 && arr1[i]<=39)
symbol[i] = "F";
code[i] = 2;
if(arr1[i]>=0 && arr1[i]<=29)
symbol[i] = "FF";
code[i] = 1;
int avcode;
string avsym;
if(avg<=100 && avg>=80 )
avcode = 7;
avsym = "A";
if(avg<=79 && avg>=70 )
avcode = 6;
avsym = "B";
if(avg<=69 && avg>=60 )
avcode = 5;
avsym = "C";
if(avg<=59 && avg>=50 )
avcode = 4;
avsym = "D";
if(avg<=49 && avg>=40 )
avcode = 3;
avsym = "E";
if(avg<=39 && avg>=30 )
avcode = 2;
avsym = "F";
if(avg<=29 && avg>=0 )
avcode = 1;
avsym = "FF";
void Dispay(string& Name, string& Surname, string& School, string (&symbol)[6] , int (&mark)[6], int (&code)[6], string (subject)[6])
cout <<"\n*******************************************************************************" << endl;
cout <<" STUDENT ACADEMIC RECORD " << endl;
cout <<" This program input the learner marks of matric level subjects and prints the student final report" << endl;
cout <<"*******************************************************************************" << endl;
cout <<"Name: " + Name + " " + Surname + " School: " + School;
cout <<"\n\nSubject \t\tMark\t\tSymbol\t\tCode" << endl;
for(int i = 0; i<6;i++)
cout << subject[i] << "\t" << mark[i]<< "%\t\t" + symbol[i] << "\t\t" << code[i] << "\n";
cout << "\nAverage Year Mark: " << " 32 " << " with symbol " << " D " << " and code " << " 4 " << endl;
cout << "\nOutcome: " << "Passed" << endl;
cout << "\nThe highest mark was: " << " -" <<high<< endl;
cout << "\nThe lowest mark was: " << " -" <<low<< endl;
cout <<"*******************************************************************************" << endl;
int main ()
string n; string sn; string s; string dec;
int Eng; int Maths; int LO; int His; int CL; int Art; //int low; int high;
double avg = 0;
string subject[] = "English ","Mathematics ","Life Orientation ","History ","Computer Literacy","Art ";
string symbol[6];
int code[6];
studentDetails(n,sn,s);
getMarks(Eng, Maths, LO, His, CL, Art);
int mark[] = Eng, Maths, LO, His, CL, Art;
AverageYearMark(avg, Eng, Maths, LO, His, CL, Art);
minMax(Eng, Maths, LO, His, CL, Art);
passorFail(dec,Eng, Maths, LO, His, CL, Art);
awardDistinction(avg, Eng, Maths, LO, His, CL, Art);
codeSymbol(symbol,code,avg,Eng,Maths,LO,His,CL,Art);
Dispay(n,sn,s,symbol,mark,code,subject);
【讨论】：
【参考方案2】：好吧，这真是一团糟！ - 你已经在很多不同的地方声明了int high 和int low。我做了一点整理（有点远不够）。在这里，我基本上删除了 int low 和 int high 的所有“阴影”实例，只使用全局实例：https://godbolt.org/z/6KWvz5
您应该做些什么来帮助自己（除了查看您的缩进和代码间距）是打开您可以得到的每个编译器警告，并确保您的代码没有警告。
还可以查找“名称阴影”，这是您的问题之一（还有其他问题）：https://www.learncpp.com/cpp-tutorial/variable-shadowing-name-hiding/
这里再次是带有警告标志-pthread -std=c++11 -Wall -Wextra -Wshadow 的编辑代码（我放回了用// THIS SHADOWS THE GLOBAL INT 注释的阴影变量之一：https://godbolt.org/z/9W3vY3
请查看所有编译器警告 - 将警告视为错误！ - 事实上，您可以使用标志 -Werror 告诉编译器执行此操作。
【讨论】：
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