listView 中获取不到checkBox的 那么属性？

Posted 2023-04-23

this.listView1.CheckedIndices// 获取列表中选中的单选框列表
this.listView1.CheckedItems// 获取列表中选中的单选框列表 参考技术A 能表达的清楚一点吗？

如何遍历并获取listview中checkbox是不是选中以及该项的id?

这是我之前解决这个问题写的东西，直接贴上来，你看下吧。

      private List<Boolean> originalFoundedDevicesState; //有一个保存状态的list

给listview绑定adapter：




private CheckAdapter foundedDevices;

private ListView foundedList;




foundedDevices=new CheckAdapter(AddingDevicesAct.this,originalFoundedDevices,originalFoundedDevicesState);




foundedList.setAdapter(foundedDevices);

foundedList.setItemsCanFocus(false);foundedList.setChoiceMode(ListView.CHOICE_MODE_MULTIPLE);

        foundedList.setOnItemClickListener(new OnItemClickListener()

         public void onItemClick(AdapterView<?> parent, View view, int position,

long id)

// TODO Auto-generated method stub

);

2.自己为checkbox复写个adapter:

class CheckAdapter extends BaseAdapter

Context mContext;

List<Device> mData;

List<Boolean>status;

LayoutInflater mInflater;

CheckBox checkBox;

    HashMap<Integer,View> lmap=new HashMap<Integer,View>();

public CheckAdapter(Context context,List<Device> data,List<Boolean> DeviceStatus)

  mInflater=LayoutInflater.from(context);

  mData=data;

  status=DeviceStatus;     

public int getCount()

// TODO Auto-generated method stub

return mData.size();

public Object getItem(int position)

// TODO Auto-generated method stub

return mData.get(position);

public long getItemId(int position)

// TODO Auto-generated method stub

return position;

public View getView(final int position, View convertView, ViewGroup parent)

// TODO Auto-generated method stub

if(lmap.get(position)==null)

convertView=mInflater.inflate(R.layout.child,parent, false);

checkBox=(CheckBox)convertView.findViewById(R.id.devices);

convertView.setTag(checkBox);

else

   checkBox=(CheckBox)convertView.getTag();

checkBox.setId(position);

checkBox.setChecked(status.get(position));

checkBox.setText(mData.get(position).toString());

checkBox.setOnCheckedChangeListener(new OnCheckedChangeListener()

public void onCheckedChanged(CompoundButton buttonView, boolean isChecked)

// TODO Auto-generated method stub

status.set(buttonView.getId(), isChecked);

notifyDataSetChanged();

);

return convertView;

    

3.最后可以根据其是否被选中状态判断某项是否被选中，并提取id:

for(num1=0;num1<originalFoundedDevicesState.size();num1++)

if(originalFoundedDevicesState.get(num1))

  finalPairedDevices.add(new Device(originalFoundedDevices.get(num1).getName(), originalFoundedDevices.get(num1).getAddress()));

参考技术A Action里面：
private PromotionManageTo promotionManageTo;
private List<PromotionManageTo> productClass;
get…
set…
JSP里面：
<s:iterator value="productClass" status="productClassLength">
<td>
<input type="checkbox" name="promotionManageTo.productId" value="<fs:property value="productId"/>" <c:if test="$fn:containsIgnoreCase(promotionManageTo.productId, productId)">checked="checked"</c:if> />
</td>
</s:iterator> 参考技术B 记录在map
里，每次选中或取消的时候记录当前位置存放到map中，每次getview的时候去查map当前位置是否被选中的。