LightOJ 1080 Binary Simulation (线段树&成段更新)

Posted 2022-12-01 synapse7

http://lightoj.com/volume_showproblem.php?problem=1080

模板。

/*0.484s,4312KB*/

#include <cstdio>
#include <cstring>
#include <algorithm>
using namespace std;
#define lson l , m , rt << 1
#define rson m + 1 , r , rt << 1 | 1
#define root 1, N, 1
#define LL int
const int mx = 100000;

LL sum[mx << 2], add[mx << 2];
char s[mx + 5];
int i;

inline void pushup(int rt)

	sum[rt] = sum[rt << 1] + sum[rt << 1 | 1];


inline void pushdown(int rt, int m)

	if (add[rt])
	
		add[rt << 1] += add[rt];
		add[rt << 1 | 1] += add[rt];///更新左右子区间add
		sum[rt << 1] += add[rt] * (m - (m >> 1));
		sum[rt << 1 | 1] += add[rt] * (m >> 1);///平分父节点add，更新左右子区间和
		add[rt] = 0;///父节点add清零
	


void build(int l, int r, int rt)

	add[rt] = 0;
	if (l == r)
	
		sum[rt] = s[i++] & 15;
		return;
	
	int m = (l + r) >> 1;
	build(lson);
	build(rson);
	pushup(rt);


void update(int ql, int qr, int c, int l, int r, int rt)

	if (ql <= l && r <= qr)
	
		add[rt] += c;///存至此，不再往下更新
		sum[rt] += (LL)c * (r - l + 1);
		return;
	
	pushdown(rt , r - l + 1);///用父节点add往下细分计算
	int m = (l + r) >> 1;
	if (ql <= m) update(ql, qr, c, lson);
	if (qr > m) update(ql, qr, c, rson);
	pushup(rt);


LL query(int ql, int qr, int l, int r, int rt)

	if (ql <= l && r <= qr)
	
		return sum[rt];
	
	pushdown(rt , r - l + 1);///用父节点add往下细分计算
	int m = (l + r) >> 1;
	LL ret = 0;
	if (ql <= m) ret += query(ql, qr, lson);
	if (qr > m) ret += query(ql, qr, rson);
	return ret;


int main()

	int t, N, m, ql, qr, pos;
	scanf("%d", &t);
	for (int cas = 1; cas <= t; ++cas)
	
		printf("Case %d:\\n", cas);
		getchar();
		gets(s + 1);
		N = strlen(s + 1);
		i = 1;
		build(root);
		scanf("%d", &m);
		while (m--)
		
			getchar();
			if (getchar() == 'I')
			
				scanf("%d%d", &ql, &qr);
				update(ql, qr, 1, root);
			
			else
			
				scanf("%d", &pos);
				puts(query(pos, pos, root) & 1 ? "1" : "0");
			
		
	
	return 0;