Linux系统shell脚本之检测系统的任意服务

Posted 2022-06-01 江湖有缘

Linux系统shell脚本之检测系统的任意服务

• 一、脚本要求
• 二、脚本内容
• 三、执行脚本

一、脚本要求

1.输入任意一个服务名，如果服务运行和没运行输出提示
2.如果服务不存在，则提示

二、脚本内容

[root@192 practice]# cat service_input.sh 
#!/bin/bash
########################################
#Author:jeven
#time:Mon 30 May 2022 12:52:08 PM CST
#filename:service_input.sh
#Script description:
########################################
EX_RUN=$(systemctl list-units --type=service --state=running |awk 'print $1' |cut -d "." -f1)
read -p "please input system service:"  service
for i in $EX_RUN
	do
		if [ $i = $service ];then
			echo "the $service  exist "
		fi
	done
echo $(systemctl list-units --type=service --state=running |awk 'print $1' |cut -d "." -f1)|grep $service  &> /dev/null
if [ $? = 0 ];then
	echo "the $service is running"
	else 
		echo "the $service  not installed,please check your system"

	fi

三、执行脚本

[root@192 practice]# sh service_input.sh 
please input system service:a1a1a1a1
the a1a1a1a1  not installed,please check your system
[root@192 practice]# sh service_input.sh 
please input system service:httpd
the httpd  not installed,please check your system
[root@192 practice]# sh service_input.sh 
please input system service:mariadb
the mariadb  exist 
the mariadb is running
[root@192 practice]#