如何判断python两个字典里面相同key对应的值是不是相等？

Posted 2023-03-20

a = 10000: 3, 10001: 100, 10002: 7, 10003: 2000, 10004: 19

c = 10000: 3, 10001: 100, 10002: 7, 10003: 200, 10004: 19, 10005: 9, 10006: 10, 10007: 17, 10008: 82, 10009: 3, 10010: 23, 10011: 11
如何判断a里面key的值和c里面相同key对应的值是否相等？

参考技术A for key in a:
if key in c:
if c[key] == a[key]:
print('key %s 相等' % key)
else:
print('key %s 不相等' % key)
else:
print('c中无key %s' % key)本回答被提问者采纳

Python两个字典key相同的值组成新字典？

dic1='福州龙湖': ['1293521.23', '620624'], '赣州龙湖': ['3050.51']
dic2='福州龙湖': ['12345', '67890'], '赣州龙湖': ['123','456']
想组成：dic3='福州龙湖': [['1293521.23', '620624'],['12345', '67890']], '赣州龙湖': [['3050.51'],['123','456']]可否实现？

按照你的要求编写的两个字典key相同的值组成新字典的Python程序如下

dic1='福州龙湖': ['1293521.23', '620624'], '赣州龙湖': ['3050.51']

dic2='福州龙湖': ['12345', '67890'], '赣州龙湖': ['123','456']

dic3=

for key in dic1:    

if dic2.get(key):

dic3[key]=[dic1[key],dic2[key]]

else:

dic3[key]=dic1[key]

for key in dic2:

if dic1.get(key):

pass

else:

dic3[key]=dic2[key]

print(dic3)

源代码(注意源代码的缩进)

运行结果

'福州龙湖': [['1293521.23', '620624'], ['12345', '67890']], '赣州龙湖': [['3050.51'], ['123', '456']]

追问

您好还有个问题如果我是多个字典组成呢？

追答

按照你的要求编写的多个字典key相同的值组成新字典的Python程序如下
def hebing(dic1,dic3):
for key in dic1:
if dic3.get(key):
dic3[key].append(dic1[key])
else:
dic3[key]=[dic1[key]]
return dic3

dic1='福州龙湖': ['1293521.23', '620624'], '赣州龙湖': ['3050.51']
dic2='福州龙湖': ['12345', '67890'], '赣州龙湖': ['123','456']
dic4='福州龙湖': ['789', '888'], '北京龙湖': ['111']
dic3=
dic3=hebing(dic1,dic3)
dic3=hebing(dic2,dic3)
dic3=hebing(dic4,dic3)
print(dic3)
源代码(注意源代码的缩进)

运行结果
'福州龙湖': [['1293521.23', '620624'], ['12345', '67890'], ['12345', '67890']], '赣州龙湖': [['3050.51'], ['123', '456']], '北京龙湖':[['111']]

参考技术A 需要你自己写判断，和操作
默认的字典更新是同key覆盖
所以