sql查询结果横向显示？

Posted 2023-03-20

正常的查询结果是图1，想要实现的效果是图2，当图1的查询结果有1000行，那图2就要显示1000列。

简单啊，先用row_number 获取 No顺序，然后通过  STUFF FOR XML PATH 获取顺序号转成字段

 通过动态SQL利用PIVOT行列

参考技术A Select fgroup,max(case when nid=1 then fnum else null end) as fnum1,max(case when nid=2 then fnum else null end) as fnum2,max(case when nid=3 then fnum else null end) as fnum3,max(case when nid=4 then fnum else null end) as fnum4,max(case when nid=5 then fnum else null end) as fnum5from table group by fgroup本回答被提问者采纳

sql复杂的子查询，横向合并结果集

第一个查询的结果集

select * from(
select c.msName,a.msId,c.msPrice, c.msPrice*COUNT(a.msId) as totalMoney,sum(a.msAmount) as totalCount    from BillConsume a right join 
 (select top 1 msTime as startTime,GETDATE() as endTime from BillConsume where DateDiff(dd,msTime,getdate())=0  order by msTime asc) b on a.msTime between b.startTime and b.endTime and a.msId!=0
left join Menus c on c.msId=a.msId   group by a.msId ,c.msName,c.msPrice)s

连接两个结果集的语句

 full join 

第二个查询的结果集

(select sum(t.totalMoney) as allTotalMoney   from (
 select c.msName,a.msId,c.msPrice, c.msPrice*COUNT(a.msId) as totalMoney,sum(a.msAmount) as totalCount  from BillConsume a right join 
 (select top 1 msTime as startTime,GETDATE() as endTime from BillConsume where DateDiff(dd,msTime,getdate())=0  order by msTime asc) b on a.msTime between b.startTime and b.endTime and a.msId!=0
left join Menus c on c.msId=a.msId   group by a.msId ,c.msName,c.msPrice)t)t

连表的条件

on 1=1