C 语言实现 php base64_encode

Posted 2020-08-09

这是在网上找到的一段代码，因为需求不同，稍微做了下修改，有需要的朋友可以直接复制使用。

unsigned char *base64_encode(const unsigned char *str, size_t length)
{
    if (NULL == str || 0 == length)
        return NULL;

    static const char base64_table[] =
    { ‘A‘, ‘B‘, ‘C‘, ‘D‘, ‘E‘, ‘F‘, ‘G‘, ‘H‘, ‘I‘, ‘J‘, ‘K‘, ‘L‘, ‘M‘,
      ‘N‘, ‘O‘, ‘P‘, ‘Q‘, ‘R‘, ‘S‘, ‘T‘, ‘U‘, ‘V‘, ‘W‘, ‘X‘, ‘Y‘, ‘Z‘,
      ‘a‘, ‘b‘, ‘c‘, ‘d‘, ‘e‘, ‘f‘, ‘g‘, ‘h‘, ‘i‘, ‘j‘, ‘k‘, ‘l‘, ‘m‘,
      ‘n‘, ‘o‘, ‘p‘, ‘q‘, ‘r‘, ‘s‘, ‘t‘, ‘u‘, ‘v‘, ‘w‘, ‘x‘, ‘y‘, ‘z‘,
      ‘0‘, ‘1‘, ‘2‘, ‘3‘, ‘4‘, ‘5‘, ‘6‘, ‘7‘, ‘8‘, ‘9‘, ‘+‘, ‘/‘, ‘\0‘
    };

    static const char base64_pad = ‘=‘;
    const unsigned char *current = str;
    //int length = strlen(str);
    unsigned char *p;
    unsigned char *result;

    if ((length + 2) < 0 || ((length + 2) / 3) >= (1 << (sizeof(int) * 8 - 2))) 
    {
        return NULL;
    }

    result = (unsigned char *)malloc(((length + 2) / 3) * 4 * sizeof(char) + 1);
    p = result;

    while (length > 2)
    { 
        *p++ = base64_table[current[0] >> 2];
        *p++ = base64_table[((current[0] & 0x03) << 4) + (current[1] >> 4)];
        *p++ = base64_table[((current[1] & 0x0f) << 2) + (current[2] >> 6)];
        *p++ = base64_table[current[2] & 0x3f];

        current += 3;
        length -= 3; 
    }

    if (length != 0)
    {
        *p++ = base64_table[current[0] >> 2];
        if (length > 1)
        {
            *p++ = base64_table[((current[0] & 0x03) << 4) + (current[1] >> 4)];
            *p++ = base64_table[(current[1] & 0x0f) << 2];
            *p++ = base64_pad;
        }
        else
        {
            *p++ = base64_table[(current[0] & 0x03) << 4];
            *p++ = base64_pad;
            *p++ = base64_pad;
        }
    }
    *p = ‘\0‘;
    return result;
}