LeetCode（数据库）- The Category of Each Member in the Store

Posted 2022-01-29 程序员牧码

题目链接：点击打开链接

题目大意：略。

解题思路：略。

AC 代码

WITH t AS(SELECT member_id, COUNT(IFNULL(charged_amount, NULL)) * 100 / COUNT(*) score
FROM Visits LEFT JOIN Purchases USING(visit_id)
GROUP BY 1)

SELECT m.member_id, m.name, CASE 
WHEN score IS NULL THEN 'Bronze'
WHEN score >= 80 THEN 'Diamond'
WHEN score >= 50 THEN 'Gold'
ELSE 'Silver'
END category
FROM Members m LEFT JOIN t USING(member_id)