Yii Framework未定义变量模型
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我尽力解决这个问题,但我似乎无法弄清楚问题出在哪里。这是我的代码:
意见/超市/ index.php文件:
<?php
use yiihelpershtml;
use yiiwidgetsLinkPager;
?>
<h1>Supermarkets</h1>
<ul>
<?php
$array = (array) $supermarkets;
$this->widget('zii.widgets.grid.CGridView', array(
'id' => 'supermarkets-grid',
'dataProvider' => $model->search(),
'filter' => $model,
'columns' => array(
'name',
'location',
'telephone',
'fax',
'website'
),
));
function build_table($array){
// start table
$html = '<table class="altrowstable" id="alternatecolor">';
// header row
$html .= '<tr>';
foreach($array[0] as $key=>$value){
$html .= '<th>' . $key . '</th>';
}
$html .= '</tr>';
// data rows
foreach( $array as $key=>$value){
$html .= '<tr>';
foreach($value as $key2=>$value2){
$html .= '<td>' . $value2 . '</td>';
}
$html .= '</tr>';
}
// finish table and return it
$html .= '</table>';
return $html;
}
echo build_table($array);
?>
<?= LinkPager::widget(['pagination' => $pagination]) ?>
Supermarkets.php:
<?php
namespace appmodels;
use yiidbActiveRecord;
class Supermarkets extends ActiveRecord
{
public function search()
{
$criteria=new CDbCriteria;
$criteria->compare('name',$this->Name,true);
$criteria->compare('location',$this->Location,true);
$criteria->compare('telephone',$this->Telephone,true);
$criteria->compare('fax',$this->Fax,true);
$criteria->compare('website',$this->Website,true);
return new CActiveDataProvider(get_class($this), array(
'criteria'=>$criteria,
'sort'=>array(
'defaultOrder'=>'name ASC',
),
'pagination'=>array(
'pageSize'=>20
),
));
}
SupermarketsController.php:
<?php
namespace appcontrollers;
use yiiwebController;
use yiidataPagination;
use appmodelsSupermarkets;
class SupermarketsController extends Controller
{
public function actionIndex()
{
$query = supermarkets::find();
$pagination = new Pagination([
'defaultPageSize' => 20,
'totalCount' => $query->count(),
]);
$supermarkets = $query->orderBy('Name')
->offset($pagination->offset)
->limit($pagination->limit)
->all();
return $this->render('index', [
'supermarkets' => $supermarkets,
'pagination' => $pagination,
]);
$model =new Supermarkets('search');
if(isset($_GET['Supermarkets']))
$model->attributes =$_GET['Supermarkets'];
return $this->render('index', array('model'=>$model));
}
public function actionName(){
$model = new Supermarkets();
$this->render('index', array('model'=>$model));
}
}
这是我得到的错误:
未定义的变量:index.php中的模型('dataProvider'=> $ model-> search())我试图根据以下问题添加搜索和过滤条件How to add Search and Filter Criteria in Yii
请你帮助我好吗?
答案
在你的SupermarketsController.php中:你有一个错误:
你已经渲染了这个
return $this->render('index', [
'supermarkets' => $supermarkets,
'pagination' => $pagination,
]);
它没有任何模型命名变量,
后来你有
$model =new Supermarkets('search');
if(isset($_GET['Supermarkets']))
$model->attributes =$_GET['Supermarkets'];
return $this->render('index', array('model'=>$model));
这将是无用的,因为你在那之前回来,
所以你可以抓住那个变量并将它与第一个渲染一起渲染
另一答案
这会奏效。您已渲染2时间索引视图。将它们合并为一个
public function actionIndex()
{
$query = supermarkets::find();
$pagination = new Pagination([
'defaultPageSize' => 20,
'totalCount' => $query->count(),
]);
$supermarkets = $query->orderBy('Name')
->offset($pagination->offset)
->limit($pagination->limit)
->all();
$model =new Supermarkets('search');
if(isset($_GET['Supermarkets']))
$model->attributes =$_GET['Supermarkets'];
return $this->render('index', array(
'model' => $model,
'supermarkets' => $supermarkets,
'pagination' => $pagination,
));
}
另一答案
你在控制器中渲染了两次,
$model =new Supermarkets('search');
if(isset($_GET['Supermarkets']))
$model->attributes =$_GET['Supermarkets'];
return $this->render('index', array(
'model' => $model,
'supermarkets' => $supermarkets,
'pagination' => $pagination,
));
请在上面的代码中替换以下代码
return $this->render('index', [
'supermarkets' => $supermarkets,
'pagination' => $pagination,
]);
$model =new Supermarkets('search');
if(isset($_GET['Supermarkets']))
$model->attributes =$_GET['Supermarkets'];
return $this->render('index', array('model'=>$model));
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