如何从PHP中的URL获取图像的大小？

Posted 2021-04-27

我一直试图从网址中获取图像的大小，但它不起作用。谁能帮我？

这是代码：

$imagesize = getimagesize('https://www.dropbox.com/s/hbtmge2omlyqx2n/BrownBag.jpg?dl=0');
echo $imagesize;

答案

你没有在这个网址中获得图像https://www.dropbox.com/s/hbtmge2omlyqx2n/BrownBag.jpg?dl=0

你需要得到的是这个https://photos-5.dropbox.com/t/2/AADa4bq7fis50BvRTojhB5zvAJDLNwsLDb5dekkb4JfilQ/12/502094097/jpeg/32x32/3/1513760400/0/2/BrownBag.jpg/EJrFv4kEGLgCIAIoAg/cwCCXcZopeYId4BrstNKJ6qGETjrin47oEgU6B50AE0?dl=0&size=1280x960&size_mode=3的图像地址

码

$imagesize = getimagesize('https://photos-5.dropbox.com/t/2/AADa4bq7fis50BvRTojhB5zvAJDLNwsLDb5dekkb4JfilQ/12/502094097/jpeg/32x32/3/1513760400/0/2/BrownBag.jpg/EJrFv4kEGLgCIAIoAg/cwCCXcZopeYId4BrstNKJ6qGETjrin47oEgU6B50AE0?dl=0&size=1280x960&size_mode=3');
print_r($imagesize);

结果

Array
(
    [0] => 1000
    [1] => 750
    [2] => 2
    [3] => width="1000" height="750"
    [bits] => 8
    [channels] => 3
    [mime] => image/jpeg
)

你也可以参考这个Dropbox get public url of the file after upload

只需更改：

https://www.dropbox.com/s/hbtmge2omlyqx2n/BrownBag.jpg?dl=0

至

https://dl.dropbox.com/s/hbtmge2omlyqx2n/BrownBag.jpg

只需用www替换dl并删除?dl=0

另一答案

您需要使用Dropbox的图像路径

$imagesize = getimagesize('https://photos-5.dropbox.com/t/2/AADa4bq7fis50BvRTojhB5zvAJDLNwsLDb5dekkb4JfilQ/12/502094097/jpeg/32x32/3/1513760400/0/2/BrownBag.jpg/EJrFv4kEGLgCIAIoAg/cwCCXcZopeYId4BrstNKJ6qGETjrin47oEgU6B50AE0?dl=0&size=1600x1200&size_mode=3');
echo $imagesize;