在laravel 5.2中使用工厂关系违反完整性约束
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我是laravel测试的新手,我正在尝试使用Model Factories创建虚拟数据。我有三张桌子:
- 公司
- 客户
- 内裤
公司有很多客户,客户有很多简报。 clients
和briefs
的格式非常相似。他们恭敬地拥有外键firm_id
和client_id
。在进行phpunit测试时,我想使用以下代码从公司创建客户端实例和客户端的简介实例:
$client = $firm->clients()
->save(factory(AppSearchFirmClient::class)->create());
$brief = $client->briefs()
->save(factory(AppSearchFirmBrief::class)->create());
$client
创建没有大惊小怪,但$brief
抛出一个错误:
IlluminateDatabaseQueryException: SQLSTATE[23000]: Integrity constraint violation: 1048 Column 'client_id' cannot be null (SQL: insert into `search_firms_briefs` (`user_id`, `title`, `description`, `contact_id`, `client_id`, `updated_at`, `created_at`) values (1, Et in amet., Quo soluta ut impedit nesciunt autem. Laborum aperiam est non molestiae animi non quod. Explicabo eligendi doloribus ex quia vitae placeat ut., 0, , 2016-03-30 10:06:34, 2016-03-30 10:06:34))
两个表的格式:
Schema::create('search_firms_clients', function(Blueprint $table)
{
$table->increments('client_id');
$table->integer('search_firm_id')->unsigned();
$table->foreign('search_firm_id')->references('id')->on('search_firms')->onDelete('cascade');
$table->string('name');
$table->softDeletes();
$table->timestamps();
});
Schema::create('search_firms_briefs', function(Blueprint $table)
{
$table->increments('brief_id');
$table->integer('client_id')->unsigned();
$table->foreign('client_id')->references('client_id')->on('search_firms_clients')->onDelete('cascade');
$table->string('title');
$table->softDeletes();
$table->timestamps();
});
每个模型工厂:
$factory->define(AppSearchFirmClient::class, function ($faker) {
return [
'name' => $faker->company,
'email' => $faker->companyEmail,
'phone' => $faker->phoneNumber,
'address' => $faker->address,
'website' => $faker->url,
];
});
$factory->define(AppSearchFirmBrief::class, function ($faker) {
return [
'user_id' => 1,
'title' => $faker->sentence(3),
'description' => $faker->text(),
'contact_id' => 0,
];
});
关系:
class SearchFirm extends Model
{
protected $table = 'search_firms';
protected $primaryKey = 'id';
public function clients() {
return $this->hasMany('SearchFirmClient', 'search_firm_id');
}
}
class SearchFirmClient extends Model
{
use SoftDeletes;
protected $table = 'search_firms_clients';
protected $primaryKey = 'client_id';
protected $dates = [ 'deleted_at' ];
public function briefs()
{
return $this->hasMany('SearchFirmBrief', 'client_id')->orderBy( 'updated_at', 'desc');
}
}
class SearchFirmBrief extends Model
{
use SoftDeletes;
protected $table = 'search_firms_briefs';
protected $primaryKey = 'brief_id';
protected $touches = array('client');
protected $dates = [ 'deleted_at'];
public function client() {
return $this->belongsTo('SearchFirmClient', 'client_id');
}
}
答案
问题#1
id
表上没有briefs
列,但是您在clients
表上引用它。
将外键更改为brief_id
:
Schema::create('search_firms_clients', function(Blueprint $table)
{
$table->increments('client_id');
$table->integer('search_firm_id')->unsigned();
$table->foreign('search_firm_id')
->references('brief_id') // <-- Change this
->on('search_firms')
->onDelete('cascade');
$table->string('name');
$table->softDeletes();
$table->timestamps();
});
Schema::create('search_firms_briefs', function(Blueprint $table)
{
$table->increments('brief_id');
$table->integer('client_id')->unsigned();
$table->foreign('client_id')->references('client_id')->on('search_firms_clients')->onDelete('cascade');
$table->string('title');
$table->softDeletes();
$table->timestamps();
});
问题#2
你没有user_id
会员。
$factory->define(AppSearchFirmBrief::class, function ($faker) {
return [
'client_id' => 1, // <-- change this
'title' => $faker->sentence(3),
'description' => $faker->text(),
'contact_id' => 0,
];
});
结论
最好遵循Laravel的命名标准,它将在未来为您节省很多麻烦(即使用默认表名,主键名)
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