如何在使用phpunit进行测试时生成会话变量
Posted
tags:
篇首语:本文由小常识网(cha138.com)小编为大家整理,主要介绍了如何在使用phpunit进行测试时生成会话变量相关的知识,希望对你有一定的参考价值。
在使用phpUnit测试一段代码(按照codeigniter mvc编写)时,我得到了错误PHP致命错误:在非对象上调用成员函数getPermissionObject()。
代码如下所示,产生错误的部分缩进。
class Some_model extends Model
{
var $userid;
var $permisson_object;
var $username;
var $userType;
var $userFirstName;
function Some_model()
{
parent::Model();
$user_obj = @unserialize($this->db_session->userdata('user_object'));
//following line shows error
$this->permisson_object = $user_obj->getPermissionObject();
$this->userid = $user_obj->getUserid();
$this->username = $user_obj->getUsername();
$this->userType =$user_obj->getusertype();
$this->userFirstName = $user_obj->getFirstName()." ".$user_obj->getLastName();
}
}
出现错误是因为在测试时我无法从我的测试类生成$ user_obj(因为它是从会话数据生成的)。
我的要求是在测试类中生成相同的内容,以便我可以使用它。
谢谢
感谢您的回复。
该对象看起来像这样:
User_library Object
(
[username:User_library:private] => staff@some.com
[firstname:User_library:private] => some
[lastname:User_library:private] => Staff
[typename:User_library:private] =>
[userid:User_library:private] => 2
[userType:User_library:private] => 2
[permissionObject:User_library:private] => Permission_library Object
(
[create_custom_attr:Permission_library:private] => 1
[create_jobspecific_attr:Permission_library:private] => 0
[injob:Permission_library:private] => Array
(
[products] => 2
[services] => 2
[options] => 2
[tasks_assigned_to_me] => 2
[tasks_assigned_to_others] => 2
)
[outjob:Permission_library:private] => Array
(
[products] => 2
[services] => 2
[options] => 2
[tasks_assigned_to_others] => 2
)
[samedept:Permission_library:private] => Array
(
)
[alldepts:Permission_library:private] => Array
(
[add_and_assign_tasks] => 4
[add_and_assign_milestones] => 4
)
)
我找不到任何模拟这个的选项,因为这个对象中还有其他对象。这里User_library Object是类User_library的对象。这里面也有Permission_library对象。我怎样才能通过以下方式模仿上述内容:
$observer = $this->getMock('Some_model', array('Some_model'));
$observer->expects($this->any())
->method('Some_model')
->with($this->equalTo('something'));
在这里我的问题是在$this->equalTo('something')
的某些部分会有什么?
你的问题的一个可能的答案是"Dependency Injection"
,坦率地说,我最喜欢的那个。只是简单的嘲笑也是可能的。
一些例子
<?php
// You could pass the session into the object while constructing it
// so in your test you can pass in a "fake" user object (see below)
class Some_model extends Model {
function Some_model($user_object) {
$user_object->yourFunctions();
}
这样你就不必依赖某些全球状态的设置正确的方式。
如果这对你不起作用(我不知道codeigniter真的很好),你可以像这样:
<?php
class Some_model extends Model {
function Some_model($user_object=null) {
if($user_obj === null) {
$user_obj = @unserialize($this->db_session->userdata('user_object'));
}
$user_object->yourFunctions();
}
因此,在您的测试中,您传入一个模拟的用户对象(您创建的假实例,对于mocking see the docs),您的普通代码不必更改。
也很好读:Slides about PHPUnit best practices from the PHPUnit Author。希望帮助澄清我试图解释的:)
编辑
sidhartha要求对模拟提供一些帮助,所以我写了一些更多的演示代码。我已经删除了大部分内容以提供完整的可执行示例,因为我猜“你可以运行的代码”比其他任何东西都更有帮助。
假设这是您要测试的代码(缩减为用户ID,因此它更短)
<?php
class Some_model extends Model
{
var $userid;
var $permisson_object;
function Some_model()
{
parent::Model();
$user_obj = @unserialize($this->db_session->userdata('user_object'));
//following line shows error
$this->permisson_object = $user_obj->getPermissionObject();
$this->userid = $user_obj->getUserid();
}
}
使用我试图解释的你可以构建一个像这样的测试(一个文件中的所有内容都可以复制粘贴eaiser,当然有人会将其拆分)
class Model { public function Model() {} }
class Some_model extends Model
{
var $userid;
var $permisson_object;
function Some_model($user_obj)
{
parent::Model();
//following line shows error
$this->userid = $user_obj->getUserid();
$this->permisson_object = $user_obj->getPermissionObject();
}
public function getThatUserid() {
// Just to show off how mocking works a little bit better :)
return $this->userid;
}
}
class Permissions {
public function getPermissions() {
// lots of code here maybe
return array("something from" => "the database");
}
}
class User {
public function getUserid() {
// code code
return 1;
}
public function getPermissionObject() {
}
}
class Some_modelTest extends PHPUnit_Framework_Testcase {
public function testConstruction() {
$mockUser = $this->getMock("User");
$mockPermissions = $this->getMock("Permission");
$mockUser->expects($this->once())
->method("getUserid")
->will($this->returnValue(100));
# $mockPermissions->expects($this->once())
# ->method("getPermissions");
// Now for the "magic"
$mockUser->expects($this->once())
->method("getPermissionObject")
->will($this->returnValue($mockPermissions));
// ^^ now we are all set and user_obj is independen of the permissons object
// Now pass the "Fake" user into the model
$model = new Some_model($mockUser);
// and just to show off the "will return value stuff"
$this->assertSame(100, $model->getThatUserid());
}
}
phpunit由Sebastian Bergmann撰写的Some_modelTest.php PHPUnit 3.4.15。
.
时间:0秒,内存:4.25Mb
好的(1个测试,3个断言)
我真的希望有所帮助。这是很多代码,但作为演示它应该适合你。
以上是关于如何在使用phpunit进行测试时生成会话变量的主要内容,如果未能解决你的问题,请参考以下文章
在单独的进程中运行测试时,PHPUnit 无法生成代码覆盖率
无法发送会话 cookie - 标头已发送 PHPUnit / Laravel
PHPUnit - 使用 $_POST 变量测试 MVC 控制器