添加filter_var后，PHP代码在SQL表中插入空值

Posted 2021-04-05

添加filter_var然后清理输入后，我的php代码现在在SQL表中插入空值。我的代码工作正常，但现在不起作用。怎么会？我正在尝试清理输入，因此没有人可以破解我的数据。

<?php
$servername = "localhost";
$username = "****";
$password = "*********";
$dbname = "app";

try {
    $conn = new PDO("mysql:host=$servername;dbname=$dbname", $username, $password);
// set the PDO error mode to exception
    $conn->setAttribute(PDO::ATTR_ERRMODE, PDO::ERRMODE_EXCEPTION);

// prepare sql and bind parameters
    $stmt = $conn->prepare("INSERT INTO MyGuests (firstname, lastname, email) VALUES (:firstname, :lastname, :email)");
    $stmt->bindParam(':firstname', $firstname);
    $stmt->bindParam(':lastname', $lastname);
    $stmt->bindParam(':email', $email);

// insert a row

    $firstname = filter_var($firstname, FILTER_SANITIZE_STRING, $_POST["firstname"]);
    $lastname = filter_var($lastname, FILTER_SANITIZE_STRING, $_POST["lastname"]);
    $email = filter_var($email, FILTER_SANITIZE_EMAIL, $_POST["email"]);
    $stmt->execute();


    echo "New records created successfully";
}
catch(PDOException $e)
{
    echo "Error: " . $e->getMessage();
}
$conn = null;
?>

答案

看起来你没有将正确的变量传递给filter_var而不检查数据是否有效。

// prepare sql and bind parameters
$stmt = $conn->prepare("INSERT INTO MyGuests (firstname, lastname, email) VALUES (:firstname, :lastname, :email)");

// Validate input *BEFORE* binding to statement
$firstname = filter_var($_POST["firstname"], FILTER_SANITIZE_STRING);
$lastname = filter_var($_POST["lastname"], FILTER_SANITIZE_STRING);
$email = filter_var($_POST["email"], FILTER_SANITIZE_EMAIL);

if ($firstname && $lastname && $email) {
    $stmt->bindParam(':firstname', $firstname);
    $stmt->bindParam(':lastname', $lastname);
    $stmt->bindParam(':email', $email);

    // insert a row
    $stmt->execute();

    echo "New records created successfully";
} else {
    echo "Failed Data Check: First Name (" . $firstname . ") - Last Name (" . $lastname . ") - EMail (" . $email . ")" ;
}

您可能想要调整最后一个调试行。