如何在java中实现md5加密和解密

Posted 2023-03-11

参考技术A package endecrypt;
02.
03.import java.io.UnsupportedEncodingException;
04.import java.security.MessageDigest;
05.import java.security.NoSuchAlgorithmException;
06.
07./**
08. * 采用MD5加密解密
09. * @author tfq
10. * @datetime 2011-10-13
11. */
12.public class MD5Util
13.
14. /***
15. * MD5加码 生成32位md5码
16. */
17. public static String string2MD5(String inStr)
18. MessageDigest md5 = null;
19. try
20. md5 = MessageDigest.getInstance("MD5");
21. catch (Exception e)
22. System.out.println(e.toString());
23. e.printStackTrace();
24. return "";
25.
26. char[] charArray = inStr.toCharArray();
27. byte[] byteArray = new byte[charArray.length];
28.
29. for (int i = 0; i < charArray.length; i++)
30. byteArray[i] = (byte) charArray[i];
31. byte[] md5Bytes = md5.digest(byteArray);
32. StringBuffer hexValue = new StringBuffer();
33. for (int i = 0; i < md5Bytes.length; i++)
34. int val = ((int) md5Bytes[i]) & 0xff;
35. if (val < 16)
36. hexValue.append("0");
37. hexValue.append(Integer.toHexString(val));
38.
39. return hexValue.toString();
40.
41.
42.
43. /**
44. * 加密解密算法 执行一次加密，两次解密
45. */
46. public static String convertMD5(String inStr)
47.
48. char[] a = inStr.toCharArray();
49. for (int i = 0; i < a.length; i++)
50. a[i] = (char) (a[i] ^ 't');
51.
52. String s = new String(a);
53. return s;
54.
55. 本回答被提问者采纳