php 以IP的形式获取访问者的地理位置

Posted 2020-08-20 百里屠苏phper

<?php
header(‘Content-Type:text/html;charset=utf-8‘);
function getIPLoc_sina($queryIP){   
$url = ‘http://int.dpool.sina.com.cn/iplookup/iplookup.php?format=json&ip=‘.$queryIP;   
$ch = curl_init($url);    
curl_setopt($ch,CURLOPT_ENCODING ,‘utf8‘);    
curl_setopt($ch, CURLOPT_TIMEOUT, 5);  
curl_setopt($ch, CURLOPT_RETURNTRANSFER, true) ; // 获取数据返回 
$location = curl_exec($ch);   
$location = json_decode($location);   
curl_close($ch);        
$loc = "";  
if($location===FALSE) return "";    
if (empty($location->desc)) {   
    $loc = $location->city.$location->district.$location->isp; 
}else{         $loc = $location->desc;
}   
return $loc;
}
echo getIPLoc_sina("211.161.160.126");
?>