laravel框架之状态更改

Posted 2020-12-02 azzy

//表单
@if($v[‘sex‘]==0)
  <td  class="se"  ss="{{$v[‘sex‘]}}"    id="{{$v[‘id‘]}}"  >男</td>
 @elseif($v[‘sex‘]==1)
  <td  class="se"  ss="{{$v[‘sex‘]}}"    id="{{$v[‘id‘]}}"  >女</td>

@endif

//jqery

$(document).on("click",".se",function () {
       id=$(this).attr("id");
       sex= $(this).attr("ss");
       str="";
       if (sex==0){
           str="男"
       }else{
           str="女"
       }

        that=$(this);
       $.ajax({
           url:"jdjg",
           type:"post",
           dataType:"json",
           data:{
               id:id,
               sex:str
           },
          success:function (data) { console.log(data);
       if (data=="男"){
           that.text("男")
           that.attr("ss",0)
       } else{
           that.text("女")
           that.attr("ss",1)
       }


          }
       })
})



//控制器

function   jdjg(req $req){
        $id=  $req->post("id");
        $sex=$req->post("sex");
//       echo  json_encode($sex);die;
        if ($sex=="男"){
            $res=DB::table("poker")->where("id",$id)->update(["sex"=>1]);
            $sex="女";
            echo  json_encode($sex);
        }else{

            $res=DB::table("poker")->where("id",$id)->update(["sex"=>0]);
            $sex="男";
            echo  json_encode($sex);
        }