php使用表单post方法进行页面

Posted 2020-10-31 BurningChen

<?php
$action = \'http://www.cnblogs.com/burningc/\';
$method = \'post\';
$key = \'\';
$val = \'\';

$shtml = "<form id=\'submit\' name=\'submit\' action=\'".$action."\' method=\'".$method."\'>";
$sHtml.= "<input type=\'hidden\' name=\'".$key."\' value=\'".$val."\'/>";
$sHtml = $sHtml."</form>";
$sHtml = $sHtml."<script>document.forms[\'submit\'].submit();</script>";

echo $sHtml;

　　

header(\'location:./test.php?i=1\');  跳转方式是以get的方式跳转