#Leetcode# 373. Find K Pairs with Smallest Sums
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https://leetcode.com/problems/find-k-pairs-with-smallest-sums/
You are given two integer arrays nums1 and nums2 sorted in ascending order and an integer k.
Define a pair (u,v) which consists of one element from the first array and one element from the second array.
Find the k pairs (u1,v1),(u2,v2) ...(uk,vk) with the smallest sums.
Example 1:
Input: nums1 = [1,7,11], nums2 = [2,4,6], k = 3
Output: [[1,2],[1,4],[1,6]]
Explanation: The first 3 pairs are returned from the sequence:
[1,2],[1,4],[1,6],[7,2],[7,4],[11,2],[7,6],[11,4],[11,6]
Example 2:
Input: nums1 = [1,1,2], nums2 = [1,2,3], k = 2 Output: [1,1],[1,1] Explanation: The first 2 pairs are returned from the sequence: [1,1],[1,1],[1,2],[2,1],[1,2],[2,2],[1,3],[1,3],[2,3]
Example 3:
Input: nums1 = [1,2], nums2 = [3], k = 3 Output: [1,3],[2,3] Explanation: All possible pairs are returned from the sequence: [1,3],[2,3]
代码1:
class Solution { public: vector<pair<int, int>> kSmallestPairs(vector<int>& nums1, vector<int>& nums2, int k) { vector<pair<int, int>> res; multimap<int, pair<int, int>> m; for (int i = 0; i < min((int)nums1.size(), k); ++i) { for (int j = 0; j < min((int)nums2.size(), k); ++j) { m.insert({nums1[i] + nums2[j], {nums1[i], nums2[j]}}); } } for (auto it = m.begin(); it != m.end(); ++it) { res.push_back(it->second); if (--k <= 0) return res; } return res; } };
代码2:
class Solution { public: vector<pair<int, int>> kSmallestPairs(vector<int>& nums1, vector<int>& nums2, int k) { vector<pair<int, int> > sum; vector<pair<int, int> > ans; int N = nums1.size(), M = nums2.size(); for(int i = 0; i < min(N, k); i ++) { for(int j = 0; j < min(M ,k); j ++) { ans.push_back({nums1[i], nums2[j]}); } } sort(ans.begin(), ans.end(), [](pair<int, int> &a, pair<int, int> &b){return a.first + a.second < b.first + b.second;}); if (ans.size() > k) ans.erase(ans.begin() + k, ans.end()); return ans; } };
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