leetcode986
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class Solution: def judgeIntersection(self,a:‘Interval‘,b:‘Interval‘): #返回值1,bool类型,是否有交集:True-有交集,False-无交集 #返回值2,int类型,哪个先结束:0-A先结束,1-B先结束,2-AB同时结束 #返回值3,Interval类型,交集的值:有交集时是Interval实例,无交集时是None intersect = False firstEnd = 2 if a.end < b.end: firstEnd = 0 elif a.end > b.end: firstEnd = 1 else: firstEnd = 2 intersectArea = Interval() if a.start <= b.start and a.end >= b.start and a.end <= b.end: #print(‘True,[b.start,a.end]‘) intersect = True intersectArea.start=b.start intersectArea.end=a.end elif a.start >= b.start and a.start <= b.end and a.end >= b.end: #print(‘True,[a.start,b.end]‘) intersect = True intersectArea.start=a.start intersectArea.end=b.end elif a.start>= b.start and a.end <= b.end: #print(‘True,[a.start,a.end]‘) intersect = True intersectArea.start=a.start intersectArea.end=a.end elif a.start<=b.start and a.end >= b.end: #print(‘True,[b.start,b.end]‘) intersect = True intersectArea.start=b.start intersectArea.end=b.end elif a.end < b.start: #print(‘False,None‘) intersect = False intersectArea = None elif a.start > b.end: #print(‘False,None‘) intersect = False intersectArea = None else: print(‘error‘) return intersect,firstEnd,intersectArea def intervalIntersection(self, A: ‘List[Interval]‘, B: ‘List[Interval]‘) -> ‘List[Interval]‘: Aindex = 0 Bindex = 0 Alen = len(A) Blen = len(B) ListI = list() while Aindex < Alen and Bindex < Blen: r1,r2,r3 = self.judgeIntersection(A[Aindex],B[Bindex]) if r1: ListI.append(r3) if r2 == 0: Aindex+=1 elif r2 == 1: Bindex+=1 else: Aindex+=1 Bindex+=1 return ListI
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