#Leetcode# 148. Sort List
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https://leetcode.com/problems/sort-list/
Sort a linked list in O(n log n) time using constant space complexity.
Example 1:
Input: 4->2->1->3 Output: 1->2->3->4
Example 2:
Input: -1->5->3->4->0 Output: -1->0->3->4->5
代码:
/** * Definition for singly-linked list. * struct ListNode { * int val; * ListNode *next; * ListNode(int x) : val(x), next(NULL) {} * }; */ class Solution { public: ListNode* sortList(ListNode* head) { if(!head || !head -> next) return head; ListNode *fast = head, *slow = head, *pre = head; while(fast && fast -> next) { pre = slow; slow = slow -> next; fast = fast -> next -> next; } pre -> next = NULL; return mergesort(sortList(head), sortList(slow)); } ListNode *mergesort(ListNode* l1, ListNode* l2) { ListNode *dummy = new ListNode(-1); ListNode *cur = dummy; while(l1 && l2) { if(l1 -> val < l2 -> val) { cur -> next = l1; l1 = l1 -> next; } else { cur -> next = l2; l2 = l2 -> next; } cur = cur -> next; } if(l1) cur -> next = l1; if(l2) cur -> next = l2; return dummy -> next; } };
归并排序 学到了
FHFHFH
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