百度地图API 判断点是否在圆形内
Posted skiwnchqhh
tags:
篇首语:本文由小常识网(cha138.com)小编为大家整理,主要介绍了百度地图API 判断点是否在圆形内相关的知识,希望对你有一定的参考价值。
/**
* @fileoverview GeoUtils类提供若干几何算法,用来帮助用户判断点与矩形、
* 圆形、多边形线、多边形面的关系,并提供计算折线长度和多边形的面积的公式。
* 主入口类是<a href="symbols/BMapLib.GeoUtils.html">GeoUtils</a>,
* 基于Baidu Map API 1.2。
*
* @author Baidu Map Api Group
* @version 1.2
*/
/**
* @namespace BMap的所有library类均放在BMapLib命名空间下
*/
var BMapLib = window.BMapLib = BMapLib || {};
(function() {
/**
* 地球半径
*/
var EARTHRADIUS = 6370996.81;
/**
* @exports GeoUtils as BMapLib.GeoUtils
*/
var GeoUtils =
/**
* GeoUtils类,静态类,勿需实例化即可使用
* @class GeoUtils类的<b>入口</b>。
* 该类提供的都是静态方法,勿需实例化即可使用。
*/
BMapLib.GeoUtils = function(){
}
/**
* 判断点是否在矩形内
* @param {Point} point 点对象
* @param {Bounds} bounds 矩形边界对象
* @returns {Boolean} 点在矩形内返回true,否则返回false
*/
GeoUtils.isPointInRect = function(point, bounds){
//检查类型是否正确
if (!(point instanceof BMap.Point) ||
!(bounds instanceof BMap.Bounds)) {
return false;
}
var sw = bounds.getSouthWest(); //西南脚点
var ne = bounds.getNorthEast(); //东北脚点
return (point.lng >= sw.lng && point.lng <= ne.lng && point.lat >= sw.lat && point.lat <= ne.lat);
}
/**
* 判断点是否在圆形内
* @param {Point} point 点对象
* @param {Circle} circle 圆形对象
* @returns {Boolean} 点在圆形内返回true,否则返回false
*/
GeoUtils.isPointInCircle = function(point, circle){
//检查类型是否正确
if (!(point instanceof BMap.Point) ||
!(circle instanceof BMap.Circle)) {
return false;
}
//point与圆心距离小于圆形半径,则点在圆内,否则在圆外
var c = circle.getCenter();
var r = circle.getRadius();
var dis = GeoUtils.getDistance(point, c);
if(dis <= r){
return true;
} else {
return false;
}
}
/**
* 判断点是否在折线上
* @param {Point} point 点对象
* @param {Polyline} polyline 折线对象
* @returns {Boolean} 点在折线上返回true,否则返回false
*/
GeoUtils.isPointOnPolyline = function(point, polyline){
//检查类型
if(!(point instanceof BMap.Point) ||
!(polyline instanceof BMap.Polyline)){
return false;
}
//首先判断点是否在线的外包矩形内,如果在,则进一步判断,否则返回false
var lineBounds = polyline.getBounds();
if(!this.isPointInRect(point, lineBounds)){
return false;
}
//判断点是否在线段上,设点为Q,线段为P1P2 ,
//判断点Q在该线段上的依据是:( Q - P1 ) × ( P2 - P1 ) = 0,且 Q 在以 P1,P2为对角顶点的矩形内
var pts = polyline.getPath();
for(var i = 0; i < pts.length - 1; i++){
var curPt = pts[i];
var nextPt = pts[i + 1];
//首先判断point是否在curPt和nextPt之间,即:此判断该点是否在该线段的外包矩形内
if (point.lng >= Math.min(curPt.lng, nextPt.lng) && point.lng <= Math.max(curPt.lng, nextPt.lng) &&
point.lat >= Math.min(curPt.lat, nextPt.lat) && point.lat <= Math.max(curPt.lat, nextPt.lat)){
//判断点是否在直线上公式
var precision = (curPt.lng - point.lng) * (nextPt.lat - point.lat) -
(nextPt.lng - point.lng) * (curPt.lat - point.lat);
if(precision < 2e-10 && precision > -2e-10){//实质判断是否接近0
return true;
}
}
}
return false;
}
/**
* 判断点是否多边形内
* @param {Point} point 点对象
* @param {Polyline} polygon 多边形对象
* @returns {Boolean} 点在多边形内返回true,否则返回false
*/
GeoUtils.isPointInPolygon = function(point, polygon){
//检查类型
if(!(point instanceof BMap.Point) ||
!(polygon instanceof BMap.Polygon)){
return false;
}
//首先判断点是否在多边形的外包矩形内,如果在,则进一步判断,否则返回false
var polygonBounds = polygon.getBounds();
if(!this.isPointInRect(point, polygonBounds)){
return false;
}
var pts = polygon.getPath();//获取多边形点
//下述代码来源:http://paulbourke.net/geometry/insidepoly/,进行了部分修改
//基本思想是利用射线法,计算射线与多边形各边的交点,如果是偶数,则点在多边形外,否则
//在多边形内。还会考虑一些特殊情况,如点在多边形顶点上,点在多边形边上等特殊情况。
var N = pts.length;
var boundOrVertex = true; //如果点位于多边形的顶点或边上,也算做点在多边形内,直接返回true
var intersectCount = 0;//cross points count of x
var precision = 2e-10; //浮点类型计算时候与0比较时候的容差
var p1, p2;//neighbour bound vertices
var p = point; //测试点
p1 = pts[0];//left vertex
for(var i = 1; i <= N; ++i){//check all rays
if(p.equals(p1)){
return boundOrVertex;//p is an vertex
}
p2 = pts[i % N];//right vertex
if(p.lat < Math.min(p1.lat, p2.lat) || p.lat > Math.max(p1.lat, p2.lat)){//ray is outside of our interests
p1 = p2;
continue;//next ray left point
}
if(p.lat > Math.min(p1.lat, p2.lat) && p.lat < Math.max(p1.lat, p2.lat)){//ray is crossing over by the algorithm (common part of)
if(p.lng <= Math.max(p1.lng, p2.lng)){//x is before of ray
if(p1.lat == p2.lat && p.lng >= Math.min(p1.lng, p2.lng)){//overlies on a horizontal ray
return boundOrVertex;
}
if(p1.lng == p2.lng){//ray is vertical
if(p1.lng == p.lng){//overlies on a vertical ray
return boundOrVertex;
}else{//before ray
++intersectCount;
}
}else{//cross point on the left side
var xinters = (p.lat - p1.lat) * (p2.lng - p1.lng) / (p2.lat - p1.lat) + p1.lng;//cross point of lng
if(Math.abs(p.lng - xinters) < precision){//overlies on a ray
return boundOrVertex;
}
if(p.lng < xinters){//before ray
++intersectCount;
}
}
}
}else{//special case when ray is crossing through the vertex
if(p.lat == p2.lat && p.lng <= p2.lng){//p crossing over p2
var p3 = pts[(i+1) % N]; //next vertex
if(p.lat >= Math.min(p1.lat, p3.lat) && p.lat <= Math.max(p1.lat, p3.lat)){//p.lat lies between p1.lat & p3.lat
++intersectCount;
}else{
intersectCount += 2;
}
}
}
p1 = p2;//next ray left point
}
if(intersectCount % 2 == 0){//偶数在多边形外
return false;
} else { //奇数在多边形内
return true;
}
}
/**
* 将度转化为弧度
* @param {degree} Number 度
* @returns {Number} 弧度
*/
GeoUtils.degreeToRad = function(degree){
return Math.PI * degree/180;
}
/**
* 将弧度转化为度
* @param {radian} Number 弧度
* @returns {Number} 度
*/
GeoUtils.radToDegree = function(rad){
return (180 * rad) / Math.PI;
}
/**
* 将v值限定在a,b之间,纬度使用
*/
function _getRange(v, a, b){
if(a != null){
v = Math.max(v, a);
}
if(b != null){
v = Math.min(v, b);
}
return v;
}
/**
* 将v值限定在a,b之间,经度使用
*/
function _getLoop(v, a, b){
while( v > b){
v -= b - a
}
while(v < a){
v += b - a
}
return v;
}
/**
* 计算两点之间的距离,两点坐标必须为经纬度
* @param {point1} Point 点对象
* @param {point2} Point 点对象
* @returns {Number} 两点之间距离,单位为米
*/
GeoUtils.getDistance = function(point1, point2){
//判断类型
if(!(point1 instanceof BMap.Point) ||
!(point2 instanceof BMap.Point)){
return 0;
}
point1.lng = _getLoop(point1.lng, -180, 180);
point1.lat = _getRange(point1.lat, -74, 74);
point2.lng = _getLoop(point2.lng, -180, 180);
point2.lat = _getRange(point2.lat, -74, 74);
var x1, x2, y1, y2;
x1 = GeoUtils.degreeToRad(point1.lng);
y1 = GeoUtils.degreeToRad(point1.lat);
x2 = GeoUtils.degreeToRad(point2.lng);
y2 = GeoUtils.degreeToRad(point2.lat);
return EARTHRADIUS * Math.acos((Math.sin(y1) * Math.sin(y2) + Math.cos(y1) * Math.cos(y2) * Math.cos(x2 - x1)));
}
/**
* 计算折线或者点数组的长度
* @param {Polyline|Array<Point>} polyline 折线对象或者点数组
* @returns {Number} 折线或点数组对应的长度
*/
GeoUtils.getPolylineDistance = function(polyline){
//检查类型
if(polyline instanceof BMap.Polyline ||
polyline instanceof Array){
//将polyline统一为数组
var pts;
if(polyline instanceof BMap.Polyline){
pts = polyline.getPath();
} else {
pts = polyline;
}
if(pts.length < 2){//小于2个点,返回0
return 0;
}
//遍历所有线段将其相加,计算整条线段的长度
var totalDis = 0;
for(var i =0; i < pts.length - 1; i++){
var curPt = pts[i];
var nextPt = pts[i + 1]
var dis = GeoUtils.getDistance(curPt, nextPt);
totalDis += dis;
}
return totalDis;
} else {
return 0;
}
}
/**
* 计算多边形面或点数组构建图形的面积,注意:坐标类型只能是经纬度,且不适合计算自相交多边形的面积
* @param {Polygon|Array<Point>} polygon 多边形面对象或者点数组
* @returns {Number} 多边形面或点数组构成图形的面积
*/
GeoUtils.getPolygonArea = function(polygon){
//检查类型
if(!(polygon instanceof BMap.Polygon) &&
!(polygon instanceof Array)){
return 0;
}
var pts;
if(polygon instanceof BMap.Polygon){
pts = polygon.getPath();
}else{
pts = polygon;
}
if(pts.length < 3){//小于3个顶点,不能构建面
return 0;
}
var totalArea = 0;//初始化总面积
var LowX = 0.0;
var LowY = 0.0;
var MiddleX = 0.0;
var MiddleY = 0.0;
var HighX = 0.0;
var HighY = 0.0;
var AM = 0.0;
var BM = 0.0;
var CM = 0.0;
var AL = 0.0;
var BL = 0.0;
var CL = 0.0;
var AH = 0.0;
var BH = 0.0;
var CH = 0.0;
var CoefficientL = 0.0;
var CoefficientH = 0.0;
var ALtangent = 0.0;
var BLtangent = 0.0;
var CLtangent = 0.0;
var AHtangent = 0.0;
var BHtangent = 0.0;
var CHtangent = 0.0;
var ANormalLine = 0.0;
var BNormalLine = 0.0;
var CNormalLine = 0.0;
var OrientationValue = 0.0;
var AngleCos = 0.0;
var Sum1 = 0.0;
var Sum2 = 0.0;
var Count2 = 0;
var Count1 = 0;
var Sum = 0.0;
var Radius = EARTHRADIUS; //6378137.0,WGS84椭球半径
var Count = pts.length;
for (var i = 0; i < Count; i++) {
if (i == 0) {
LowX = pts[Count - 1].lng * Math.PI / 180;
LowY = pts[Count - 1].lat * Math.PI / 180;
MiddleX = pts[0].lng * Math.PI / 180;
MiddleY = pts[0].lat * Math.PI / 180;
HighX = pts[1].lng * Math.PI / 180;
HighY = pts[1].lat * Math.PI / 180;
}
else if (i == Count - 1) {
LowX = pts[Count - 2].lng * Math.PI / 180;
LowY = pts[Count - 2].lat * Math.PI / 180;
MiddleX = pts[Count - 1].lng * Math.PI / 180;
MiddleY = pts[Count - 1].lat * Math.PI / 180;
HighX = pts[0].lng * Math.PI / 180;
HighY = pts[0].lat * Math.PI / 180;
}
else {
LowX = pts[i - 1].lng * Math.PI / 180;
LowY = pts[i - 1].lat * Math.PI / 180;
MiddleX = pts[i].lng * Math.PI / 180;
MiddleY = pts[i].lat * Math.PI / 180;
HighX = pts[i + 1].lng * Math.PI / 180;
HighY = pts[i + 1].lat * Math.PI / 180;
}
AM = Math.cos(MiddleY) * Math.cos(MiddleX);
BM = Math.cos(MiddleY) * Math.sin(MiddleX);
CM = Math.sin(MiddleY);
AL = Math.cos(LowY) * Math.cos(LowX);
BL = Math.cos(LowY) * Math.sin(LowX);
CL = Math.sin(LowY);
AH = Math.cos(HighY) * Math.cos(HighX);
BH = Math.cos(HighY) * Math.sin(HighX);
CH = Math.sin(HighY);
CoefficientL = (AM * AM + BM * BM + CM * CM) / (AM * AL + BM * BL + CM * CL);
CoefficientH = (AM * AM + BM * BM + CM * CM) / (AM * AH + BM * BH + CM * CH);
ALtangent = CoefficientL * AL - AM;
BLtangent = CoefficientL * BL - BM;
CLtangent = CoefficientL * CL - CM;
AHtangent = CoefficientH * AH - AM;
BHtangent = CoefficientH * BH - BM;
CHtangent = CoefficientH * CH - CM;
AngleCos = (AHtangent * ALtangent + BHtangent * BLtangent + CHtangent * CLtangent) / (Math.sqrt(AHtangent * AHtangent + BHtangent * BHtangent + CHtangent * CHtangent) * Math.sqrt(ALtangent * ALtangent + BLtangent * BLtangent + CLtangent * CLtangent));
AngleCos = Math.acos(AngleCos);
ANormalLine = BHtangent * CLtangent - CHtangent * BLtangent;
BNormalLine = 0 - (AHtangent * CLtangent - CHtangent * ALtangent);
CNormalLine = AHtangent * BLtangent - BHtangent * ALtangent;
if (AM != 0)
OrientationValue = ANormalLine / AM;
else if (BM != 0)
OrientationValue = BNormalLine / BM;
else
OrientationValue = CNormalLine / CM;
if (OrientationValue > 0) {
Sum1 += AngleCos;
Count1++;
}
else {
Sum2 += AngleCos;
Count2++;
}
}
var tempSum1, tempSum2;
tempSum1 = Sum1 + (2 * Math.PI * Count2 - Sum2);
tempSum2 = (2 * Math.PI * Count1 - Sum1) + Sum2;
if (Sum1 > Sum2) {
if ((tempSum1 - (Count - 2) * Math.PI) < 1)
Sum = tempSum1;
else
Sum = tempSum2;
}
else {
if ((tempSum2 - (Count - 2) * Math.PI) < 1)
Sum = tempSum2;
else
Sum = tempSum1;
}
totalArea = (Sum - (Count - 2) * Math.PI) * Radius * Radius;
return totalArea; //返回总面积
}
})();//闭包结束
- 1
- 2
- 3
- 4
- 5
- 6
- 7
- 8
- 9
- 10
- 11
- 12
- 13
- 14
- 15
- 16
- 17
- 18
- 19
- 20
- 21
- 22
- 23
- 24
- 25
- 26
- 27
- 28
- 29
- 30
- 31
- 32
- 33
- 34
- 35
- 36
- 37
- 38
- 39
- 40
- 41
- 42
- 43
- 44
- 45
- 46
- 47
- 48
- 49
- 50
- 51
- 52
- 53
- 54
- 55
- 56
- 57
- 58
- 59
- 60
- 61
- 62
- 63
- 64
- 65
- 66
- 67
- 68
- 69
- 70
- 71
- 72
- 73
- 74
- 75
- 76
- 77
- 78
- 79
- 80
- 81
- 82
- 83
- 84
- 85
- 86
- 87
- 88
- 89
- 90
- 91
- 92
- 93
- 94
- 95
- 96
- 97
- 98
- 99
- 100
- 101
- 102
- 103
- 104
- 105
- 106
- 107
- 108
- 109
- 110
- 111
- 112
- 113
- 114
- 115
- 116
- 117
- 118
- 119
- 120
- 121
- 122
- 123
- 124
- 125
- 126
- 127
- 128
- 129
- 130
- 131
- 132
- 133
- 134
- 135
- 136
- 137
- 138
- 139
- 140
- 141
- 142
- 143
- 144
- 145
- 146
- 147
- 148
- 149
- 150
- 151
- 152
- 153
- 154
- 155
- 156
- 157
- 158
- 159
- 160
- 161
- 162
- 163
- 164
- 165
- 166
- 167
- 168
- 169
- 170
- 171
- 172
- 173
- 174
- 175
- 176
- 177
- 178
- 179
- 180
- 181
- 182
- 183
- 184
- 185
- 186
- 187
- 188
- 189
- 190
- 191
- 192
- 193
- 194
- 195
- 196
- 197
- 198
- 199
- 200
- 201
- 202
- 203
- 204
- 205
- 206
- 207
- 208
- 209
- 210
- 211
- 212
- 213
- 214
- 215
- 216
- 217
- 218
- 219
- 220
- 221
- 222
- 223
- 224
- 225
- 226
- 227
- 228
- 229
- 230
- 231
- 232
- 233
- 234
- 235
- 236
- 237
- 238
- 239
- 240
- 241
- 242
- 243
- 244
- 245
- 246
- 247
- 248
- 249
- 250
- 251
- 252
- 253
- 254
- 255
- 256
- 257
- 258
- 259
- 260
- 261
- 262
- 263
- 264
- 265
- 266
- 267
- 268
- 269
- 270
- 271
- 272
- 273
- 274
- 275
- 276
- 277
- 278
- 279
- 280
- 281
- 282
- 283
- 284
- 285
- 286
- 287
- 288
- 289
- 290
- 291
- 292
- 293
- 294
- 295
- 296
- 297
- 298
- 299
- 300
- 301
- 302
- 303
- 304
- 305
- 306
- 307
- 308
- 309
- 310
- 311
- 312
- 313
- 314
- 315
- 316
- 317
- 318
- 319
- 320
- 321
- 322
- 323
- 324
- 325
- 326
- 327
- 328
- 329
- 330
- 331
- 332
- 333
- 334
- 335
- 336
- 337
- 338
- 339
- 340
- 341
- 342
- 343
- 344
- 345
- 346
- 347
- 348
- 349
- 350
- 351
- 352
- 353
- 354
- 355
- 356
- 357
- 358
- 359
- 360
- 361
- 362
- 363
- 364
- 365
- 366
- 367
- 368
- 369
- 370
- 371
- 372
- 373
- 374
- 375
- 376
- 377
- 378
- 379
- 380
- 381
- 382
- 383
- 384
- 385
- 386
- 387
- 388
- 389
- 390
- 391
- 392
- 393
- 394
- 395
- 396
- 397
- 398
- 399
- 400
- 401
- 402
- 403
- 404
- 405
- 406
- 407
- 408
- 409
- 410
- 411
- 412
- 413
- 414
- 415
- 416
- 417
- 418
- 419
- 420
- 421
- 422
- 423
- 424
- 425
- 426
- 427
- 428
- 429
- 430
- 431
- 432
- 433
- 434
- 435
- 436
- 437
- 438
- 439
- 440
- 441
- 442
- 443
- 444
- 445
- 446
- 447
- 448
- 449
- 450
- 451
- 452
使用方法:
var point = new BMap.Point(x,y)
var circle = new BMap.Circle(mPoint,1000,{fillColor:"blue", strokeWeight: 1 ,fillOpacity: 0.3, strokeOpacity: 0.3});
if(BMapLib.GeoUtils.isPointInCircle(point,circle)){
alert("该point在circle内");
}
- 1
- 2
- 3
- 4
- 5
- 6
链接:GeoUtils.js
作者:itmyhome
再分享一下我老师大神的人工智能教程吧。零基础!通俗易懂!风趣幽默!还带黄段子!希望你也加入到我们人工智能的队伍中来!https://blog.csdn.net/jiangjunshow
以上是关于百度地图API 判断点是否在圆形内的主要内容,如果未能解决你的问题,请参考以下文章
在百度地图上手绘了一个多边形,随便用鼠标点击地图获取改点坐标,并判断是不是属于在手绘的多边形内