LeetCode-17-Letter Combinations of a Phone Number
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算法描述:
Given a string containing digits from 2-9
inclusive, return all possible letter combinations that the number could represent.
A mapping of digit to letters (just like on the telephone buttons) is given below. Note that 1 does not map to any letters.
Example:
Input: "23" Output: ["ad", "ae", "af", "bd", "be", "bf", "cd", "ce", "cf"].
Note:
Although the above answer is in lexicographical order, your answer could be in any order you want.
解题思路:
对于输出所有可能的组合这一类型题目,第一时间就应该想到采用回溯法。其中重点就是确定回溯的对象,本题中回溯的对象就是往结果中存的字符串。因为要考虑所有状况,所以处理完之后要还原回来。
vector<string> letterCombinations(string digits) { vector<string> results; if(digits.size()<=0) return results; string dict[] = {"", "", "abc","def","ghi","jkl","mno","pqrs","tuv","wxyz"}; Combination(digits,0,results,dict, ""); return results; } void Combination(string digits, int level, vector<string>& results, string dict[], string curr){ if(level==digits.size()){ results.push_back(curr); return; } int index = digits[level] - ‘0‘; string tmp = dict[index]; for(int i=0; i < tmp.size(); i++){ string next = curr + tmp[i]; Combination(digits, level+1, results, dict, next); } }
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