#Leetcode# 82. Remove Duplicates from Sorted List II
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https://leetcode.com/problems/remove-duplicates-from-sorted-list-ii/
Given a sorted linked list, delete all nodes that have duplicate numbers, leaving only distinct numbers from the original list.
Example 1:
Input: 1->2->3->3->4->4->5 Output: 1->2->5
Example 2:
Input: 1->1->1->2->3 Output: 2->3
代码:
/** * Definition for singly-linked list. * struct ListNode { * int val; * ListNode *next; * ListNode(int x) : val(x), next(NULL) {} * }; */ class Solution { public: ListNode* deleteDuplicates(ListNode* head) { if(!head || !head ->next) return head; ListNode *dummy = new ListNode(-1), *pre = dummy; dummy -> next = head; while(pre -> next) { ListNode *cur = pre -> next; while(cur -> next && cur -> val == cur -> next -> val) cur = cur -> next; if(cur != pre -> next) pre -> next = cur -> next; else pre = pre -> next; } return dummy ->next; } };
有可能头结点就是重复的是要被删除的 所以要 dummy
FHFHFH
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