LeetCode 599. Minimum Index Sum of Two Lists

Posted 2021-01-25 A-Little-Nut

Suppose Andy and Doris want to choose a restaurant for dinner, and they both have a list of favorite restaurants represented by strings.

You need to help them find out their common interest with the least list index sum. If there is a choice tie between answers, output all of them with no order requirement. You could assume there always exists an answer.

Example 1:

Input:
["Shogun", "Tapioca Express", "Burger King", "KFC"]
["Piatti", "The Grill at Torrey Pines", "Hungry Hunter Steakhouse", "Shogun"]
Output: ["Shogun"]
Explanation: The only restaurant they both like is "Shogun".

Example 2:

Input:
["Shogun", "Tapioca Express", "Burger King", "KFC"]
["KFC", "Shogun", "Burger King"]
Output: ["Shogun"]
Explanation: The restaurant they both like and have the least index sum is "Shogun" with index sum 1 (0+1).

Note:

• The length of both lists will be in the range of [1, 1000].
• The length of strings in both lists will be in the range of [1, 30].
• The index is starting from 0 to the list length minus 1.
• No duplicates in both lists.

class Solution {
public:
    vector<string> findRestaurant(vector<string>& list1, vector<string>& list2) {
                   vector<string> res;
                   int minsum=999999;
                   for(int i=0; i<list1.size(); i++){
                        auto it=find(list2.begin(), list2.end(),list1[i]);
                        if(it!=list2.end()){
                        if((it-list2.begin())+i<minsum){
                            res.clear();
                            res.push_back(list1[i]);
                            minsum=it-list2.begin()+i;
                        }else if(it-list2.begin()+i==minsum)
                            res.push_back(list1[i]);
                        }     
                   }
                   return res;   
                      
    }
};