LeetCode 401. Binary Watch

Posted 2021-01-24 A-Little-Nut

A binary watch has 4 LEDs on the top which represent the hours (0-11), and the 6 LEDs on the bottom represent the minutes (0-59).

Each LED represents a zero or one, with the least significant bit on the right.

For example, the above binary watch reads “3:25”.

Given a non-negative integer n which represents the number of LEDs that are currently on, return all possible times the watch could represent.

Example:

Input: n = 1
Return: ["1:00", "2:00", "4:00", "8:00", "0:01", "0:02", "0:04", "0:08", "0:16", "0:32"]

Note:

• The order of output does not matter.
• The hour must not contain a leading zero, for example “01:00” is not valid, it should be “1:00”.
• The minute must be consist of two digits and may contain a leading zero, for example “10:2” is not valid, it should be “10:02”.

class Solution {
public:
    vector<string> readBinaryWatch(int num) { //用bitset
        vector<string> result;
        for(int h = 0; h < 12; h++) {
            for(int m = 0; m < 60; m++) {
                bitset<10> b(h << 6 | m);
                if(b.count() == num) { //获得二进制中1的个数
                    string temp = to_string(h) + ":";
                    if(m < 10)
                        temp += "0";
                    temp += to_string(m);
                    result.push_back(temp);
                }
            }
        }
        return result;
    }
};