#Leetcode# 155. Min Stack
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https://leetcode.com/problems/min-stack/
Design a stack that supports push, pop, top, and retrieving the minimum element in constant time.
- push(x) -- Push element x onto stack.
- pop() -- Removes the element on top of the stack.
- top() -- Get the top element.
- getMin() -- Retrieve the minimum element in the stack.
Example:
MinStack minStack = new MinStack(); minStack.push(-2); minStack.push(0); minStack.push(-3); minStack.getMin(); --> Returns -3. minStack.pop(); minStack.top(); --> Returns 0. minStack.getMin(); --> Returns -2.
代码:
class MinStack { public: /** initialize your data structure here. */ MinStack() {} void push(int x) { s1.push(x); if (s2.empty() || x <= s2.top()) s2.push(x); } void pop() { if (s1.top() == s2.top()) s2.pop(); s1.pop(); } int top() { return s1.top(); } int getMin() { return s2.top(); } private: stack<int> s1, s2; }; /** * Your MinStack object will be instantiated and called as such: * MinStack obj = new MinStack(); * obj.push(x); * obj.pop(); * int param_3 = obj.top(); * int param_4 = obj.getMin(); */
用两个栈来存 $s2$ 用来存最小的 第一次写这样的题 不是很会看了题解才知道怎么写 下次注意!
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