#Leetcode# 69. Sqrt(x)
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https://leetcode.com/problems/sqrtx/
Implement int sqrt(int x)
.
Compute and return the square root of x, where x is guaranteed to be a non-negative integer.
Since the return type is an integer, the decimal digits are truncated and only the integer part of the result is returned.
Example 1:
Input: 4 Output: 2
Example 2:
Input: 8 Output: 2 Explanation: The square root of 8 is 2.82842..., and since the decimal part is truncated, 2 is returned.
代码:
class Solution { public: int mySqrt(int x) { int ans = (int)sqrt(x); return ans; } };
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