#Leetcode# 69. Sqrt(x)

Posted 丧心病狂工科女

tags:

篇首语:本文由小常识网(cha138.com)小编为大家整理,主要介绍了#Leetcode# 69. Sqrt(x)相关的知识,希望对你有一定的参考价值。

https://leetcode.com/problems/sqrtx/

 

Implement int sqrt(int x).

Compute and return the square root of x, where x is guaranteed to be a non-negative integer.

Since the return type is an integer, the decimal digits are truncated and only the integer part of the result is returned.

Example 1:

Input: 4
Output: 2

Example 2:

Input: 8
Output: 2
Explanation: The square root of 8 is 2.82842..., and since 
             the decimal part is truncated, 2 is returned.

代码:

class Solution {
public:
    int mySqrt(int x) {
        int ans = (int)sqrt(x);
        return ans;
    }
};

  

以上是关于#Leetcode# 69. Sqrt(x)的主要内容,如果未能解决你的问题,请参考以下文章

Leetcode 69. Sqrt(x)

leetcode二分 | 牛顿迭代法69_Sqrt(x)

LeetCode 69. Sqrt(x)

#Leetcode# 69. Sqrt(x)

[LeetCode] 69. Sqrt(x)

69. Sqrt(x)(LeetCode)