#Leetcode# 58. Length of Last Word

Posted 2021-01-17 丧心病狂工科女

https://leetcode.com/problems/length-of-last-word/description/

 

Given a string s consists of upper/lower-case alphabets and empty space characters ‘ ‘, return the length of last word in the string.

If the last word does not exist, return 0.

Note: A word is defined as a character sequence consists of non-space characters only.

Example:

Input: "Hello World"
Output: 5

代码：

class Solution {
public:
    int lengthOfLastWord(string s) {
        int len = s.length();
        int ans = 0;
        int temp = 0;
        for(int i = len - 1; i >= 0; i --) {
            if(s[i] != ‘ ‘) {
                temp = i;
                break;
            }
        }
        for(int i = temp; i >= 0; i --) {
            if(s[i] != ‘ ‘)
                ans ++;
            else break;
        }
        return ans;
    }
};