LeetCode 70. Climbing Stairs
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分析
难度 易
来源
https://leetcode.com/problems/climbing-stairs/
题目
You are climbing a stair case. It takes n steps to reach to the top.
Each time you can either climb 1 or 2 steps. In how many distinct ways can you climb to the top?
Note: Given n will be a positive integer.
Example 1:
Input: 2
Output: 2
Explanation: There are two ways to climb to the top.
1. 1 step + 1 step
2. 2 steps
Example 2:
Input: 3
Output: 3
Explanation: There are three ways to climb to the top.
1. 1 step + 1 step + 1 step
2. 1 step + 2 steps
3. 2 steps + 1 step
解答
Runtime: 2 ms, faster than 100.00% of Java online submissions for Climbing Stairs.
1 package LeetCode; 2 3 public class L70_ClimbingStairs { 4 //n个台阶的楼梯的走法等于: 5 //ways(n) = ways(n-1) + ways(n-2) 6 public int climbStairs(int n) { 7 int pre1=0,pre2=1,ways=0;//两步前的走法数、一步前的走法数 8 if(n<=0){ 9 return n; 10 } 11 for(int i=1;i<=n;i++) 12 { 13 ways=pre1+pre2; 14 pre1=pre2; 15 pre2=ways; 16 } 17 return ways; 18 } 19 }
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