leetcode543 - Diameter of Binary Tree - easy
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Given a binary tree, you need to compute the length of the diameter of the tree. The diameter of a binary tree is the length of the longest path between any two nodes in a tree. This path may or may not pass through the root.
Example:
Given a binary tree
1
/
2 3
/
4 5
Return 3, which is the length of the path [4,2,1,3] or [5,2,1,3].
Note: The length of path between two nodes is represented by the number of edges between them.
树的递归
问题转化:对每个节点,计算左深度+右深度的值,就是经过该节点的最长path的edge数。
那如果对每个节点都得到过这个值,并且和全局变量打擂台,那就得到答案了呀。经过某个节点得到的最长path对应的长度就被存储在全局变量里了。
递归函数返回当前节点的深度给父亲用。递归函数内借助孩子打擂台。
实现:
/** * Definition for a binary tree node. * public class TreeNode { * int val; * TreeNode left; * TreeNode right; * TreeNode(int x) { val = x; } * } */ class Solution { int maxLen = 0; public int diameterOfBinaryTree(TreeNode root) { calHelper(root); return maxLen; } /* * return the current depth. leaf node has depth of 1. */ private int calHelper(TreeNode root) { if (root == null) { return 0; } int leftDepth = calHelper(root.left); int rightDepth = calHelper(root.right); maxLen = Math.max(maxLen, leftDepth + rightDepth); return Math.max(leftDepth, rightDepth) + 1; } }
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