shell脚本定时清除messages日志及TAG为none的docker images

Posted 2021-01-11

#!/bin/bash
logstatus=du -sh /var/log/messages
docker_image=docker images
docker_none=docker images|grep none
docker_rm=docker images|grep none|awk ‘{print $3 }‘
disk=df -h
cleanlog()
{
echo "######start clean messages#######"
echo "目前日志大小 $logstatus"
read -p "是否清理messages日志，请输入(yes/no)： " messlog
if [ ${messlog} = "yes" ];then
cat /dev/null > /var/log/messages
logstatus=du -sh /var/log/messages
echo -e "清理后 $logstatus"

if [ ${messlog} = "no" ];then
    exit 0
fi

fi
return 0
}
cleandockerimage()
{
echo "######start clean docker image#######"
if [ -n "${docker_rm}" ];then
echo -e "删除以下TAG为"none"的doncker images $docker_none"
else
echo -e "============================================================================== 无TAG为none的docker image 已退出当前脚本"
exit 0
fi

read -p "是否继续删除，请输入(yes/no) " delimage
if [ ${delimage} = "yes" ];then
for i in ${docker_rm}
do
docker rmi -f ${i}
echo "=============================================================================="
echo -e "删除成功：docker images列表 $docker_image"
done
if [ ${delimage} = "no" ];then
exit 0
fi
fi
return 0
}

echo -e "目前磁盘状态 ============================================================================== $disk"
echo -e " ============================================================================== 磁盘垃圾清理"
echo -e "1.清理系统日志 2.清理Docker镜像 3.Clean All !!!"
read -p "请按序号输入选择后续操作 ： " choose

if [ $choose -eq 1 ];then
sleep 1;
echo "=============================================================================="
cleanlog
fi
if [ $choose -eq 2 ];then
sleep 1;
echo "=============================================================================="
cleandockerimage
fi
if [ $choose -eq 3 ];then
cleanlog
cleandockerimage
fi