[leetcode-914-X of a Kind in a Deck of Cards]
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In a deck of cards, each card has an integer written on it.
Return true
if and only if you can choose X >= 2
such that it is possible to split the entire deck into 1 or more groups of cards, where:
- Each group has exactly
X
cards. - All the cards in each group have the same integer.
Example 1:
Input: [1,2,3,4,4,3,2,1]
Output: true
Explanation: Possible partition [1,1],[2,2],[3,3],[4,4]
Example 2:
Input: [1,1,1,2,2,2,3,3]
Output: false
Explanation: No possible partition.
Example 3:
Input: [1]
Output: false
Explanation: No possible partition.
Example 4:
Input: [1,1]
Output: true
Explanation: Possible partition [1,1]
Example 5:
Input: [1,1,2,2,2,2]
Output: true
Explanation: Possible partition [1,1],[2,2],[2,2]
Note:
1 <= deck.length <= 10000
0 <= deck[i] < 10000
思路:
直接暴力,首先,x一定能整除deck的长度n。而且x也一定能整除group里每一个元素个数。
bool hasGroupsSizeX(vector<int>& deck) { int n = deck.size(); if(n <= 1)return false; map<int,int>mp; for(int i = 0; i < n; i++){mp[deck[i]]++;} for(int x = 2; x <= n; x++) { if( n % x != 0)continue; for(auto it = mp.begin(); ;) { if(it->second % x != 0) { break;} it ++; if(it == mp.end()){return true;} } } return false; }
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914. X of a Kind in a Deck of Cards