Linux shell 脚本小记2

Posted 2020-08-22 qingyezhu

1、从文件读取
while read line
do
    echo "line=$line"
done < file.txt

2、将字符串转换为数组，并进行遍历
str="html, css, javascript, java, php, go, python"
arr=(${str//,/ })
for item in ${arr[@]}
do
    echo "item=$item"
done

3、将目录转换为字符串
ls | xargs -d‘\t‘ echo |awk ‘BEGIN{i=0;} { if(i > 0){ printf(",");} i++;printf("%s", $0);}‘

4、递归

function find(){
    local dir=$1
    local arr=( $(ls $dir) )

    for item in ${arr[@]}
    do
        local path="$dir/$item"
        if [ -L $path ]
        then
            echo "ln $path"
            find $path
        elif [ -d $path ]
        then
            echo "dir $path"
            find $path
        else
            echo "file path=$path, dir=${path%/*}, filename=${path##*/}"
        fi
    done
}

备注：
获取当前路径下的目录：${path%/*}
获取当前路径下的文件名：${path##*/}