LeetCode208. 实现 Trie (前缀树)(相关话题:字典树,前缀树)
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import java.util.TreeMap; class Trie { private class Node{ public boolean isWord; public TreeMap<Character, Node> next; public Node(boolean isWord){ this.isWord = isWord; next = new TreeMap<>(); } public Node(){ this(false); } } private Node root; /** Initialize your data structure here. */ public Trie() { root = new Node(); } /** Inserts a word into the trie. */ public void insert(String word) { Node cur = root; for(int i = 0; i < word.length(); i++){ char c = word.charAt(i); if(cur.next.get(c) == null){ cur.next.put(c, new Node()); } cur = cur.next.get(c); } cur.isWord = true; } /** Returns if the word is in the trie. */ public boolean search(String word) { Node cur = root; for(int i = 0 ; i < word.length(); i++){ char c = word.charAt(i); if(cur.next.get(c) == null){ return false; } cur = cur.next.get(c); } return cur.isWord; } /** Returns if there is any word in the trie that starts with the given prefix. */ public boolean startsWith(String prefix) { Node cur = root; for(int i = 0; i < prefix.length(); i++){ char c = prefix.charAt(i); if(cur.next.get(c) == null){ return false; } cur = cur.next.get(c); } return true; } } /** * Your Trie object will be instantiated and called as such: * Trie obj = new Trie(); * obj.insert(word); * boolean param_2 = obj.search(word); * boolean param_3 = obj.startsWith(prefix); */
Solution 2 (比使用TreeMap时间效率高): 【40讲系列10】字典树
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