leetcode 53. Maximum Subarray
Posted qwfand
tags:
篇首语:本文由小常识网(cha138.com)小编为大家整理,主要介绍了leetcode 53. Maximum Subarray相关的知识,希望对你有一定的参考价值。
leetcode 53. Maximum Subarray
链接
描述
Given an integer array nums, find the contiguous subarray (containing at least one number) which has the largest sum and return its sum.
Example:
Input: [-2,1,-3,4,-1,2,1,-5,4],
Output: 6
Explanation: [4,-1,2,1] has the largest sum = 6.
Follow up:
If you have figured out the O(n) solution, try coding another solution using the divide and conquer approach, which is more subtle.
solution
solution1 在线处理
思路:用maxSum记录最大子列和,用thisSum记录当前处理的和,如果发现当前子列和未负,则舍弃。
class Solution {
public:
int maxSubArray(vector<int>& nums) {
int maxSum = -2147483648, thisSum = 0;
for(int i = 0; i < nums.size(); i++)
{
thisSum += nums[i];
if(thisSum > maxSum)
maxSum = thisSum;
if( thisSum < 0)
thisSum = 0;
}
return maxSum;
}
};
分析:
时间复杂度:O(N)
空间复杂度:O(1)
以上是关于leetcode 53. Maximum Subarray的主要内容,如果未能解决你的问题,请参考以下文章