[刷题] LeetCode 203 Remove Linked List Elements
Posted cxc1357
tags:
篇首语:本文由小常识网(cha138.com)小编为大家整理,主要介绍了[刷题] LeetCode 203 Remove Linked List Elements相关的知识,希望对你有一定的参考价值。
要求
- 在链表中删除值为val的所有节点
示例
- 如 1->2->3->4->5->6->NULL,要求删除值为6的节点
- 返回1->2->3->4->5->NULL
思路
- 删除一般元素(包括最后一个元素)
- 删除第一个元素
实现
- 常规思路
1 #include <iostream> 2 using namespace std; 3 4 struct ListNode { 5 int val; 6 ListNode *next; 7 ListNode(int x) : val(x), next(NULL) {} 8 }; 9 10 ListNode* createLinkedList(int arr[], int n){ 11 if( n == 0 ) 12 return NULL; 13 ListNode* head = new ListNode(arr[0]); 14 ListNode* curNode = head; 15 for( int i = 1 ; i < n ; i ++ ){ 16 curNode->next = new ListNode(arr[i]); 17 curNode = curNode->next; 18 } 19 return head; 20 } 21 22 void printLinkedList(ListNode* head){ 23 ListNode* curNode = head; 24 while( curNode != NULL ){ 25 cout << curNode->val << " -> "; 26 curNode = curNode->next; 27 } 28 cout<<"NULL"<<endl; 29 return; 30 } 31 32 void deleteLinkedList(ListNode* head){ 33 ListNode* curNode = head; 34 while( curNode != NULL){ 35 ListNode* delNode = curNode; 36 curNode = curNode->next; 37 delete delNode; 38 } 39 return; 40 } 41 42 class Solution { 43 public: 44 ListNode* removeElements(ListNode* head, int val) { 45 46 while( head != NULL && head->val == val ){ 47 ListNode* delNode = head; 48 head = delNode->next; 49 delete delNode; 50 } 51 52 if( head == NULL ) 53 return NULL; 54 55 ListNode* cur = head; 56 while( cur->next != NULL ){ 57 58 if( cur->next->val == val ){ 59 ListNode* delNode = cur->next; 60 cur->next = delNode->next; 61 delete delNode; 62 }else 63 cur = cur->next; 64 } 65 return head; 66 } 67 }; 68 69 int main(){ 70 int arr[] = {1,2,3,4,5}; 71 int n = sizeof(arr)/sizeof(int); 72 73 ListNode* head = createLinkedList(arr,n); 74 Solution().removeElements(head,3); 75 printLinkedList(head); 76 77 deleteLinkedList(head); 78 return 0; 79 }
- 设置虚拟头节点
1 #include <iostream> 2 using namespace std; 3 4 struct ListNode { 5 int val; 6 ListNode *next; 7 ListNode(int x) : val(x), next(NULL) {} 8 }; 9 10 ListNode* createLinkedList(int arr[], int n){ 11 if( n == 0 ) 12 return NULL; 13 ListNode* head = new ListNode(arr[0]); 14 ListNode* curNode = head; 15 for( int i = 1 ; i < n ; i ++ ){ 16 curNode->next = new ListNode(arr[i]); 17 curNode = curNode->next; 18 } 19 return head; 20 } 21 22 void printLinkedList(ListNode* head){ 23 ListNode* curNode = head; 24 while( curNode != NULL ){ 25 cout << curNode->val << " -> "; 26 curNode = curNode->next; 27 } 28 cout<<"NULL"<<endl; 29 return; 30 } 31 32 void deleteLinkedList(ListNode* head){ 33 ListNode* curNode = head; 34 while( curNode != NULL){ 35 ListNode* delNode = curNode; 36 curNode = curNode->next; 37 delete delNode; 38 } 39 return; 40 } 41 42 class Solution { 43 public: 44 ListNode* removeElements(ListNode* head, int val) { 45 46 ListNode* dummyHead = new ListNode(0); 47 dummyHead->next = head; 48 49 ListNode* cur = dummyHead; 50 while( cur->next != NULL ){ 51 52 if( cur->next->val == val ){ 53 ListNode* delNode = cur->next; 54 cur->next = delNode->next; 55 delete delNode; 56 }else 57 cur = cur->next; 58 } 59 60 ListNode* retNode = dummyHead->next; 61 delete dummyHead; 62 63 return retNode; 64 } 65 }; 66 67 int main(){ 68 int arr[] = {1,2,3,4,5}; 69 int n = sizeof(arr)/sizeof(int); 70 71 ListNode* head = createLinkedList(arr,n); 72 Solution().removeElements(head,3); 73 printLinkedList(head); 74 75 deleteLinkedList(head); 76 return 0; 77 }
相关
- 82 Remove Duplicates from Sorted List II
- 21 Merge Two Sorted Lists
以上是关于[刷题] LeetCode 203 Remove Linked List Elements的主要内容,如果未能解决你的问题,请参考以下文章
[JavaScript 刷题] 链表 - 移除链表元素, leetcode 203
[LeetCode]203. Remove Linked List Elements
#Leetcode# 203. Remove Linked List Elements
Java [Leetcode 203]Remove Linked List Elements