python将多个时间段相加时分秒满60自动向前+1，求最后时间总和

Posted 2023-05-06

A = ['12:06:30', '13:01:00', '11:58:32', '12:08:46', '15:13:17', '12:22:40', '11:49:31', '12:59:53', '12:08:40',
'11:36:18', '11:29:59', '11:13:27', '13:55:53', '13:05:10', '11:09:10', '10:41:00', '11:16:28', '12:33:28']

A = ['12:06:30', '13:01:00', '11:58:32', '12:08:46', '15:13:17', '12:22:40', '11:49:31', '12:59:53', '12:08:40',
'11:36:18', '11:29:59', '11:13:27', '13:55:53', '13:05:10', '11:09:10', '10:41:00', '11:16:28', '12:33:28']

total_time = 0

# 计算列表内所有时间的总秒数
for one in A:
res_time = one.split(':')
hour = int(res_time[0])*3600
minate = int(res_time[1])*60
total_time+=hour+minate+int(res_time[2])

# print(total_time)
# 取模，通过divmod函数获得商和余数
total_hour = divmod(total_time,3600)[0] # 计算小时数
total_min = divmod(divmod(total_time,3600)[1],60)[0] # 计算分钟数
total_s = total_time%3600%60 # 计算秒数
# 格式化输出
print(f'最后时间总和total_time秒，转化为时间是total_hour:total_min:total_s')

参考技术A

题主你好,

代码见截图:

执行结果见截图:

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本回答被提问者采纳 参考技术B 代码：
A = ['12:06:30', '13:01:00', '11:58:32', '12:08:46', '15:13:17', '12:22:40', '11:49:31', '12:59:53', '12:08:40',
'11:36:18', '11:29:59', '11:13:27', '13:55:53', '13:05:10', '11:09:10', '10:41:00', '11:16:28', '12:33:28']
s=[0,0,0]
for e in A:
e=tuple(map(int,e.split(':')))
for i in range(len(e)):
s[i]+=e[i]
for i in range(-1,-3,-1):
s[i]%=60
s[i-1]+=s[i]//60
print(':'.join(map(str,s)))追答

截图：

参考技术C A = ['12:06:30', '13:01:00', '11:58:32', '12:08:46', '15:13:17', '12:22:40', '11:49:31', '12:59:53', '12:08:40','11:36:18', '11:29:59', '11:13:27', '13:

时间相减得到时分秒

public function secToTime($times){
    $result = ‘00:00:00‘;
    if ($times>0) {
        $hour = floor($times/3600);
        $minute = floor(($times-3600 * $hour)/60);
        $second = floor((($times-3600 * $hour) - 60 * $minute) % 60);

        $result = $this->len($hour).‘:‘.$this->len($minute).‘:‘.$this->len($second);
    }
    return $result;
}

public function len($str){
    if(strlen($str) == 1){
        $time = ‘0‘.$str;
    }else{
        $time = $str;
    }
    return $time;
}