Leetcode: Sum of Two Integers
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Calculate the sum of two integers a and b, but you are not allowed to use the operator + and -. Example: Given a = 1 and b = 2, return 3.
转自https://discuss.leetcode.com/topic/49771/java-simple-easy-understand-solution-with-explanation/2,注意里面对于减法的讲解
have been confused about bit manipulation for a very long time. So I decide to do a summary about it here.
"&" AND operation, for example, 2 (0010) & 7 (0111) => 2 (0010)
"^" XOR operation, for example, 2 (0010) ^ 7 (0111) => 5 (0101)
"~" NOT operation, for example, ~2(0010) => -3 (1101) what??? Don‘t get frustrated here. It‘s called two‘s complement.
1111 is -1, in two‘s complement
1110 is -2, which is ~2 + 1, ~0010 => 1101, 1101 + 1 = 1110 => 2
1101 is -3, which is ~3 + 1
so if you want to get a negative number, you can simply do ~x + 1
Reference:
https://en.wikipedia.org/wiki/Two%27s_complement
https://www.cs.cornell.edu/~tomf/notes/cps104/twoscomp.html
For this, problem, for example, we have a = 1, b = 3,
In bit representation, a = 0001, b = 0011,
First, we can use "and"("&") operation between a and b to find a carry.
carry = a & b, then carry = 0001
Second, we can use "xor" ("^") operation between a and b to find the different bit, and assign it to a,
Then, we shift carry one position left and assign it to b, b = 0010.
Iterate until there is no carry (or b == 0)
1 // Iterative 2 public int getSum(int a, int b) { 3 if (a == 0) return b; 4 if (b == 0) return a; 5 6 while (b != 0) { 7 int carry = a & b; 8 a = a ^ b; 9 b = carry << 1; 10 } 11 12 return a; 13 } 14 15 // Iterative 16 public int getSubtract(int a, int b) { 17 while (b != 0) { 18 int borrow = (~a) & b; 19 a = a ^ b; 20 b = borrow << 1; 21 } 22 23 return a; 24 } 25 26 // Recursive 27 public int getSum(int a, int b) { 28 return (b == 0) ? a : getSum(a ^ b, (a & b) << 1); 29 } 30 31 // Recursive 32 public int getSubtract(int a, int b) { 33 return (b == 0) ? a : getSubtract(a ^ b, (~a & b) << 1); 34 } 35 36 // Get negative number 37 public int negate(int x) { 38 return ~x + 1; 39 }
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