httpclient能通过get类型请求发送json数据吗?
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https://www.baidu.com/p?param=z ,譬如 通过这个url来传送,应该如何实现呢?看好多例子都是post的形式。
参考技术A http://www.tuicool.com/articles/Unumeu,里面有get和post请求。HttpClient4.X发送Get请求的url参数拼接
HttpClient4.X发送Get请求的参数拼接
使用httpClient发送get请求时,请求参数可以以?key=val&key1=val1的拼接到url后面。
但是请求参数较多时,这种方法比较麻烦,也不太优雅;研究了一下发现HttpClient4.X本身
是支持处理参数的。
1. 使用 URIBuilder来构建请求URI
httpclient相关的jar包mvn依赖:
<dependency>
<groupId>org.apache.httpcomponents</groupId>
<artifactId>httpcore</artifactId>
<version>4.4.3</version>
</dependency>
<dependency>
<groupId>org.apache.httpcomponents</groupId>
<artifactId>httpclient</artifactId>
<version>4.5.1</version>
</dependency>
import com.google.common.collect.Lists;
import org.apache.http.Consts;
import org.apache.http.HttpEntity;
import org.apache.http.HttpStatus;
import org.apache.http.NameValuePair;
import org.apache.http.client.config.RequestConfig;
import org.apache.http.client.entity.UrlEncodedFormEntity;
import org.apache.http.client.methods.CloseableHttpResponse;
import org.apache.http.client.methods.HttpGet;
import org.apache.http.client.utils.URIBuilder;
import org.apache.http.impl.client.CloseableHttpClient;
import org.apache.http.impl.client.HttpClients;
import org.apache.http.message.BasicNameValuePair;
import org.apache.http.util.EntityUtils;
private HttpGet buildHttpGet(String url, Map<String, String> para)
throws URISyntaxException {
URIBuilder builder = new URIBuilder(url);
Set<String> set = para.keySet();
for(String key: set){
builder.setParameter(key, para.get(key));
}
HttpGet request = new HttpGet(builder.build());
RequestConfig requestConfig = RequestConfig.custom()
.setSocketTimeout(6000)
.setConnectTimeout(6000)
.setConnectionRequestTimeout(6000).build();
request.setConfig(requestConfig);
System.out.println(request.getURI().toString());
return request;
}
2. 使用 NameValuePair 来拼接URI
List<NameValuePair> params = Lists.newArrayList();
params.add(new BasicNameValuePair("cityEname", "henan"));
String str = "";
//转换为键值对
str = EntityUtils.toString(new UrlEncodedFormEntity(params, Consts.UTF_8));
System.out.println(str);
HttpGet httpGet = new HttpGet(url + "?" + str);
3. 根据 HttpGet反向获取键值对列表
HttpGet request = new HttpGet("http://example.com/?var=1&var=2");
URIBuilder newBuilder = new URIBuilder(request.getURI());
//获取键值对列表
List<NameValuePair> params = newBuilder.getQueryParams();
//转换为键值对字符串
String str = EntityUtils.toString(new UrlEncodedFormEntity(params, Consts.UTF_8));
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