Set Matrix Zeroes 题解
题目来源：https://leetcode.com/problems/set-matrix-zeroes/description/
Description
Given a m x n matrix, if an element is 0, set its entire row and column to 0. Do it in place.
Follow up:
Did you use extra space?
A straight forward solution using O(mn) space is probably a bad idea.
A simple improvement uses O(m + n) space, but still not the best solution.
Could you devise a constant space solution?
Solution
class Solution {
public:
void setZeroes(vector<vector<int>>& matrix) {
int row = matrix.size(), col = matrix[0].size();
int i, j, col0 = 1;
for (i = 0; i < row; i++) {
if (matrix[i][0] == 0)
col0 = 0;
for (j = 1; j < col; j++) {
if (matrix[i][j] == 0) {
matrix[i][0] = matrix[0][j] = 0;
}
}
}
for (i = row - 1; i >= 0; i--) {
for (j = col - 1; j >= 1; j--) {
if (matrix[i][0] == 0 || matrix[0][j] == 0)
matrix[i][j] = 0;
}
if (col0 == 0)
matrix[i][0] = 0;
}
}
};解题描述
这道题题意是，给出一个矩阵，对其中为0，将其所在的列和行全部置为零。而附加的条件是，要求解法只有常数空间复杂度。上面给出的解法思想在于，在矩阵第一列保存所有行的状态，在矩阵第一行保存所有列的状态，而matrix[0][0]位置会出现重叠，所以要多用一个变量col0来保存第0列的状态。