web项目中处理捕获异常统一处理

Posted 2020-10-24 love_debug

1.jfinal 中设置拦截器

2.在拦截器 捕获异常信息统一处理

 1 public class ExceptionInterceptor implements Interceptor {
 2 
 3     //@Override
 4     public void intercept(Invocation ai) {
 5         BaseController controller = (BaseController) ai.getController();
 6         HttpServletRequest request = controller.getRequest();
 7         boolean successed = false;
 8         String exception = "";
 9         try {
10             ai.invoke();
11             successed = true;
12         } catch (Exception e) {
13             e.printStackTrace();
14             successed = false;
15             // 判断是否ajax请求
16             String header = request.getHeader("X-Requested-With");
17             boolean isAjax = "XMLHttpRequest".equalsIgnoreCase(header);
18             String msg = e.getMessage();
19             exception = Exceptions.getStackTraceAsString(e);
20             controller.keepPara();
21             if (isAjax) {
22                 msg = new StringBuilder().append("{\"source\":\"ExceptionInterceptor\",\"code\":\"1\",\"message\":\"系统异常：").append(msg).append("\"}").toString();
23                 controller.renderJson(msg);
24             } else {
25                 String redirctUrl = request.getHeader("referer");
26                 if (StringUtils.isBlank(redirctUrl)) {
27                     redirctUrl = request.getRequestURI();
28                 }
29                 controller.setAttr("message", msg);
30                 controller.setAttr("stack", exception);
31                 controller.setAttr("redirctUrl", redirctUrl);
32                 controller.render("/WEB-INF/views/error/500.jsp");
33             }
34         } finally {
35 
36         }
37         return;
38 
39     }
40 
41 }

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