Description
Given an array S of n integers, find three integers in S such that the sum is closest to a given number, target. Return the sum of the three integers. You may assume that each input would have exactly one solution.
For example, given array S = {-1 2 1 -4}, and target = 1.
The sum that is closest to the target is 2. (-1 + 2 + 1 = 2).
思路
题意：给出一串整数值序列，求取最接近目标值的三个数的和
题解：按照3Sum的思路然后更新与目标值最接近的三个数的和
class Solution {
//22ms
public int threeSumClosest(int[] nums, int target) {
Arrays.sort(nums);
int res = 0,min = Integer.MAX_VALUE;
int len = nums.length;
for (int i = 0;i < len - 2;i++){
int goal = target - nums[i];
int left = i + 1,right = len - 1;
while (left < right){
int sum = nums[i] + nums[left] + nums[right];
if (sum == target){
return sum;
}
if (Math.abs(target - sum) < min){
res = sum;
min = Math.abs(target - sum);
}
if (nums[left] + nums[right] < goal){
left++;
}else if (nums[left] + nums[right] > goal){
right--;
}
}
}
return res;
}
}