LeetCode 674. Longest Continuous Increasing Subsequence （最长连续递增序列）

Posted 2020-10-11 几米空间

Given an unsorted array of integers, find the length of longest continuous increasing subsequence.

Example 1:

Input: [1,3,5,4,7]
Output: 3
Explanation: The longest continuous increasing subsequence is [1,3,5], its length is 3. 
Even though [1,3,5,7] is also an increasing subsequence, it\'s not a continuous one where 5 and 7 are separated by 4. 

 

Example 2:

Input: [2,2,2,2,2]
Output: 1
Explanation: The longest continuous increasing subsequence is [2], its length is 1. 

 

Note: Length of the array will not exceed 10,000.

 

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题目标签：Array

　　题目给了一个没有排序的nums array，让我们找到其中最长连续递增序列的长度。

　　维护一个maxLen，每次遇到递增数字就tempLen++，遇到一个不是递增数字的话，就把tempLen 和maxLen 中大的保存到maxLen。

 

 

Java Solution:

Runtime beats 69.72% 

完成日期：10/21/2017

关键词：Array

关键点：维护一个maxLen

 1 class Solution 
 2 {
 3     public int findLengthOfLCIS(int[] nums) 
 4     {
 5         if(nums == null || nums.length == 0)
 6             return 0;
 7         
 8         int maxLen = 0;
 9         int tempLen = 1;
10         
11         for(int i=1; i<nums.length; i++)
12         {
13             if(nums[i] <= nums[i-1])
14             {
15                 maxLen = Math.max(maxLen, tempLen);
16                 tempLen = 1;
17             }
18             else
19             {
20                 tempLen++;
21             }
22             
23         }
24         
25         return Math.max(maxLen, tempLen);
26     }
27 }

参考资料：N/A

 

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