[LeetCode] 128. Longest Consecutive Sequence
Posted
tags:
篇首语:本文由小常识网(cha138.com)小编为大家整理,主要介绍了[LeetCode] 128. Longest Consecutive Sequence相关的知识,希望对你有一定的参考价值。
Description
Given an unsorted array of integers, find the length of the longest consecutive elements sequence.
For example,
Given [100, 4, 200, 1, 3, 2],
The longest consecutive elements sequence is [1, 2, 3, 4]. Return its length: 4
.
Your algorithm should run in O(n) complexity.
思路
题意:给定一个未排序的数组,问最长的连续的数值有多少个。
题解:unordered_set内部用hash实现,均摊复杂度为O(1),那么我们可以遍历数组中的这些数,将其向左向右延伸,并且在延伸查找的同时进行删除,减少重复遍历的次数。
class Solution {
public:
//13ms
int longestConsecutive(vector<int>& nums) {
unordered_set<int>s(nums.begin(),nums.end());
int res = 0;
for (auto val : nums){
if (!s.count(val)) continue;
int pre = --val,next = ++val;
while (s.count(pre)) s.erase(pre--);
while (s.count(next)) s.erase(next++);
res = max(res,next - pre - 1);
}
return res;
}
};
以上是关于[LeetCode] 128. Longest Consecutive Sequence的主要内容,如果未能解决你的问题,请参考以下文章
LeetCode 128. Longest Consecutive Sequence
Leetcode(128) Longest Consecutive Sequence
LeetCode128 Longest Consecutive Sequence
128. Longest Consecutive Sequence(leetcode)