随机数算法

Posted 2022-12-10 CZandQZ

   今天给大家讲一下 最简单的随机数，例如杀了一个boss怪会掉落一件装备，这件装备呢可能是长剑，重斧，盾牌，弓箭等等这几种可能，但是每种可能都是有一定概率的，我们一般都不会给概率，假如我们先给他们的概率分别是10%，40%，20%，30%这样非要使得他们的概率和等于1，如果我们需要添加一种的话，那么久需要重新分配了，这样就会影响工作效率，所以一般的我们是给出他们的权重，例如分别为2,3,4,6这种比例，如果需要添加一种的长矛的话我们可以随便给他一个权重10，权重越大表示这种情况占比越大。所以思想就是给们分配一个区间一样例如[0,2],[2,5],[5,9],[9,15]，然后我们随机一个数检查这个值在哪个区间，在这个区间的话就代表满足这种情况，思想其实简单，写起来爷比较容易。所以我这里就直接贴出代码，大家把他当成一个工具就行了，不用自己去写。

using System.Collections.Generic;
using UnityEngine;

public class ChanceRoll

    private struct Possibility
    
        public int index;
        public float rarity;
        public bool finished;

        public Possibility(int index, float rarity, bool finished)
        
            this.index = index;
            this.rarity = rarity;
            this.finished = finished;
        
    ;

    private struct Thing
    
        float from;
        float to;
        public Possibility pos;

        public Thing(float from, float to, Possibility pos)
        
            this.from = from;
            this.to = to;
            this.pos = pos;
        

        //Returns whether or not the given number is within from and to (inclusive)
        public bool isInside(float number)
        
            return number >= from && number <= to;
        
    ;

    private List<Possibility> list;

    private bool takeAwayPossibilityAfterRoll;

    //if takeAway is true, then the posibility that occurs after a roll is taken out of the next posibilities.
    public ChanceRoll(bool takeAway = false)
    
        list = new List<Possibility>();
        takeAwayPossibilityAfterRoll = takeAway;
    


    public void Add(float rarity)
    
        list.Add(new Possibility(list.Count, rarity, false));
    


    public int Count()
    
        return list.Count;
    


    //Returns the index of the rolled possibility.
    public int Roll()
    
        float from = 0;
        float to = 0;

        List<Thing> t = new List<Thing>();

        for (int i = 0; i < list.Count; i++)
        
            if (list[i].finished) continue;

            to += list[i].rarity;

            t.Add(new Thing(from, to, list[i]));

            from = to;
        

        float randomNumber = Random.Range(0, to);
        int winningListIndex = -1;
        for (int i = 0; i < t.Count; i++)
        
            if (t[i].isInside(randomNumber))
            
                winningListIndex = t[i].pos.index;
                break;
            
        

        if (winningListIndex == -1) return -1;

        if (takeAwayPossibilityAfterRoll)
        
            list[winningListIndex] = new Possibility(list[winningListIndex].index, list[winningListIndex].rarity,
                true);
        

        return winningListIndex;
    

用法简单贴一下

 

using UnityEngine;

[ExecutionOrder(1)]
public class Test2 : MonoBehaviour



    private ChanceRoll changRoll;
    private void Start()
    
        Debug.LogError("dddddddddd");
        changRoll=new ChanceRoll();

        changRoll.Add(5);//0
        changRoll.Add(7);//1
        changRoll.Add(8);//2
        changRoll.Add(10);//3


        for (int i = 0; i < 4; i++)
        
            Debug.LogError(changRoll.Roll());
        
    

 

通过chanceRoll.Roll方法得到一个值这个值可能是0,1,2,3这个值取决于你chanceRoll数组的长度。